Arrays 从数组中的正则表达式推送每个新匹配项

我尝试解析一些xml文件，代码如下：

   function parseXml() {
      var url = 'http://www.inpo.ru/documents/pricelists/pricelist.xml';
      var xml = UrlFetchApp.fetch(url).getContentText();

      var parseregexp = new RegExp (/.*em><no>(\d+)<\/no><title>(.+?)<\/title><price vat="\w+">(\d+.\d+|\d+)<\/price><unit>(.+?)<\/unit><free>(\d+)<\/free>(.|\s)*?<it/g)
      var parsedData = '$1 $2 $3 $4 $5 '
      var rangeRegex = [];

      var Pdata = xml.replace(parseregexp,parsedData)

      var ss = SpreadsheetApp.getActiveSpreadsheet().getActiveSheet()
      ss.getRange(1, 1).setValue(Pdata)
      }

在Pdata中的这个示例中，我从所有正则表达式匹配中得到了1个长字符串。如何从所有匹配项中生成包含5列的数组？我想把每一场比赛都推到阵列上，但不知道这是怎么回事。如果您有任何帮助，我们将不胜感激

替代解决方案： 因为您试图访问xml数据，所以可以使用

然而，在fetch调用中似乎出现了问题，我无法获取整个数据。fetch提供了一个截断的文件，可能是超时的16mb文件，因此我下载了数据文件并将其上载到google drive。 此文件可用于解析XML数据，如下所示：

function parseXml() {

      var file = DriveApp.getFileById("Xml File ID")   //Get the id of the uploaded file and replace it for "Xml File ID"
      var xml = file.getBlob().getDataAsString()
      // The below code gave a error for XML parser
     /*var url = 'http://www.inpo.ru/documents/pricelists/pricelist.xml';
       var options = {
       'method' : 'get',
       'contentType': 'application/xml',
       }
      var xml = UrlFetchApp.fetch(url,options).getBlob().getDataAsString()
      Logger.log(xml)*/
     // End of code with gave an error

 var arrayItems = []
 var XmlElem = ["no","title","price","unit","free"]       //Elements to look for
 var document = XmlService.parse(xml);
 var RCounter = 0
 var groups = document.getRootElement().getChildren();   //GetGroup Element
    for(var k = 0; k< groups.length; k++){               // Loop through each group element
      var main = groups[k].getChildren()                // Get sub groups in each group
  for (var j=0 ; j < main.length; j++){                 // Loop through each subGroups

   var mainChilds = main[j].getChildren()               //Get items in each subGroups
   for (var l = 0 ; l < mainChilds.length; l++){        // Loop through each items
   var items = mainChilds[l].getChildren();             // Get  elemetns like "no","title","price","units","free" in each item 
     arrayItems[RCounter] = []
   var total = 0;
    for (var i = 0; i < items.length; i++) {
     // Logger.log(items[i].getName())
      var index = XmlElem.indexOf(items[i].getName())       //Look for items and place the value at corresponding index
      if(index != -1)
        arrayItems[RCounter][index] = items[i].getValue()
     }  //End Loope for elements
     if(arrayItems[RCounter].length > 0)                   //in case the array is empty, reuse it
      RCounter++
    }   // End loop for items
    }   // End loop for sub Groups
    }   // End loop for Groups
  Logger.log(arrayItems) 
}

---

希望有帮助

您应该发布分配给变量Pdata的值。否则我们必须运行您的代码。我们不应该那样做。看起来您可能需要将数据拆分为数组中的元素。@SandyGood是的，您是对的，我在问题中添加了它。您想将内容拆分到哪里？48514和48515？我想在单元格A2和A3中存储48514和48515。在B2 C2 D2 E2和B3 C3 D3 E3中，从$2$3$4$5 entires到$3$4$5 entires的下一场比赛，您已经厌倦了使用它！是的，它很好用，杰克！结合下载功能，它提供了刷新数据的绝佳工具。但我只有一个问题，如果我只是更改XmlElem var，那么这段代码是否适用于其他具有不同结构的xml文件？如果xml文件的结构保持不变，是的！上面的解决方案寻找以下结构{group}{group}{item}{XML元素}{/item}{/group}{/group}{/group}嘿，杰克！你们创作的剧本一直完美到今天。。我有一个错误：XML文档结构必须在同一个实体中开始和结束。at字符串：var document=XmlService.parsexml；我假设该文件可能会加载错误，将来如何避免？如果这对你来说很困难，那么如果我的评论没有得到回答也没关系

48514 The workpiece is the rod d 8x150mm P6AM5 HRC 64-66" CNIC" 154.58 Pcs 59 48515 The workpiece is the rod d 8x200mm P6AM5 HRC 64-66"CNIC" 198.24 pcs 32

function parseXml() {

      var file = DriveApp.getFileById("Xml File ID")   //Get the id of the uploaded file and replace it for "Xml File ID"
      var xml = file.getBlob().getDataAsString()
      // The below code gave a error for XML parser
     /*var url = 'http://www.inpo.ru/documents/pricelists/pricelist.xml';
       var options = {
       'method' : 'get',
       'contentType': 'application/xml',
       }
      var xml = UrlFetchApp.fetch(url,options).getBlob().getDataAsString()
      Logger.log(xml)*/
     // End of code with gave an error

 var arrayItems = []
 var XmlElem = ["no","title","price","unit","free"]       //Elements to look for
 var document = XmlService.parse(xml);
 var RCounter = 0
 var groups = document.getRootElement().getChildren();   //GetGroup Element
    for(var k = 0; k< groups.length; k++){               // Loop through each group element
      var main = groups[k].getChildren()                // Get sub groups in each group
  for (var j=0 ; j < main.length; j++){                 // Loop through each subGroups

   var mainChilds = main[j].getChildren()               //Get items in each subGroups
   for (var l = 0 ; l < mainChilds.length; l++){        // Loop through each items
   var items = mainChilds[l].getChildren();             // Get  elemetns like "no","title","price","units","free" in each item 
     arrayItems[RCounter] = []
   var total = 0;
    for (var i = 0; i < items.length; i++) {
     // Logger.log(items[i].getName())
      var index = XmlElem.indexOf(items[i].getName())       //Look for items and place the value at corresponding index
      if(index != -1)
        arrayItems[RCounter][index] = items[i].getValue()
     }  //End Loope for elements
     if(arrayItems[RCounter].length > 0)                   //in case the array is empty, reuse it
      RCounter++
    }   // End loop for items
    }   // End loop for sub Groups
    }   // End loop for Groups
  Logger.log(arrayItems) 
}