Arrays 仅查询嵌套数组中的数字

Arrays 仅查询嵌套数组中的数字,arrays,mongodb,aggregation-framework,average,Arrays,Mongodb,Aggregation Framework,Average,我试图获取文档中嵌套数组中键的平均数,但不确定如何实现这一点 以下是我的文档的外观: { "_id": { "$oid": "XXXXXXXXXXXXXXXXX" }, "data": { "type": "PlayerRoundData", "playerId": "XXXXXXXXXXXXX", "groupId": "XXXXXXXXXXXXXX", "holeScores": [ { "type": "Rou

我试图获取文档中嵌套数组中键的平均数,但不确定如何实现这一点

以下是我的文档的外观:

{
  "_id": {
    "$oid": "XXXXXXXXXXXXXXXXX"
  },
  "data": {
    "type": "PlayerRoundData",
    "playerId": "XXXXXXXXXXXXX",
    "groupId": "XXXXXXXXXXXXXX",
    "holeScores": [
      {
        "type": "RoundHoleData",
        "points": 2
      },
      {
        "type": "RoundHoleData",
        "points": 13
      },
      {
        "type": "RoundHoleData",
        "points": 3
      },
      {
        "type": "RoundHoleData",
        "points": 1
      },
      {
        "type": "RoundHoleData",
        "points": 21
      }
    ]
  }
}
现在,棘手的部分是,我只想要所有具有此playerid和此groupid的文档的holeScores[0]的平均分数

实际上,最好的解决方案是使用playerid和groupid收集所有文档,并创建一个新数组,平均值为holeScores[0]、holeScores[1]、holeScores[2]。。。但是,如果我一次只能获得一个数组键,则可以:-)

以下是我的想法,但不确定如何组合:

var allScores = dbCollection('scores').aggregate(
    {$match: {"data.groupId": groupId, "playerId": playerId}},
    {$group: {
        _id: playerId, 
        rounds: { $sum: 1 }
        result: { $sum: "$data.scoreTotals.points" }
    }}
);

真的希望在此问题上获得帮助,并提前感谢:-)

您可以在下面尝试

db.collection.aggregate(
  { "$match": { "data.groupId": groupId, "data.playerId": playerId }},
  { "$group": {
    "_id": null,
    "result": {
      "$sum": {
        "$arrayElemAt": [
          "$data.holeScores.points",
          0
        ]
      }
    }
  }}
)
您可以使用with
includearayindex
获取索引,然后使用
$group
按该索引分组

dbCollection('scores').aggregate(
    {
        $match: { "data.playerId": "XXXXXXXXXXXXX", "data.groupId": "XXXXXXXXXXXXXX" }
    },
    {
        $unwind: {
            path: "$data.holeScores",
            includeArrayIndex: "index"
        }
    },
    {
        $group: {
            _id: "$index",
            playerId: { $first: "data.playerId" }, 
            avg: { $avg: "$data.holeScores.points" }
        }
    }
)

它会出现以下错误:函数聚合不接受参数(对象)。?有什么想法吗?它出现了这个错误:函数聚合不接受参数(对象)。?有什么好主意吗?太好了,它很管用。不过我有一个问题。在平均值数组出现之前,是否也可以在输出中获得playerid?@Mansa当然,修改了我的答案