Asp.net mvc 如何在MVC4WebAPI中接收XmlDocument?

Asp.net mvc 如何在MVC4WebAPI中接收XmlDocument?,asp.net-mvc,api,web,xmldocument,Asp.net Mvc,Api,Web,Xmldocument,我正在将XmlDocument发布到ApiController(从windows服务,服务运行良好,发布正确,我在wcf web api中使用了它),但xml总是空的,我做错了什么? 我可以发布一些课程,比如教程,或者获取任何数据,一切都会好起来,但我不能发布XmlDocument public class XmlController : ApiController { public void PostXml(XmlDocument xml) { // code

我正在将XmlDocument发布到ApiController(从windows服务,服务运行良好,发布正确,我在wcf web api中使用了它),但xml总是空的,我做错了什么? 我可以发布一些课程,比如教程,或者获取任何数据,一切都会好起来,但我不能发布XmlDocument

public class XmlController : ApiController
{
    public void PostXml(XmlDocument xml)
    {
       // code
    }
}

PostXml
应该是控制器上的操作吗?如果是这样,您应该将控制器操作标记为接受HttpPost。在此基础上,我将对操作进行如下修改:

[HttpPost]
public ActionResult PostXml(HttpPostedFileBase xml)
{
    // code
}
如果您仍然无法接受发布的文件,请启动调试器并检查请求文件集合:

我找到了一个解决方案:

我们需要使用继承来继承MediaTypeFormatter

public class XmlMediaTypeFormatter : MediaTypeFormatter
{
    public XmlMediaTypeFormatter()
    {
        SupportedMediaTypes.Add(new MediaTypeHeaderValue("text/xml"));      
    }

    public override System.Threading.Tasks.Task<object> ReadFromStreamAsync(Type type, Stream stream,
         HttpContentHeaders contentHeaders,
         IFormatterLogger formatterLogger)
    {
        var taskCompletionSource = new TaskCompletionSource<object>();
        try
        {
            var memoryStream = new MemoryStream();
            stream.CopyTo(memoryStream);
            var s = System.Text.Encoding.UTF8.GetString(memoryStream.ToArray());

            XmlDocument xmlDoc = new XmlDocument();
            xmlDoc.LoadXml(s);

            taskCompletionSource.SetResult(xmlDoc);
        }
        catch (Exception e)
        {
            taskCompletionSource.SetException(e);
        }
        return taskCompletionSource.Task;
    }

    public override bool CanReadType(Type type)
    {
        return type == typeof(XmlDocument);
    }

    public override bool CanWriteType(Type type)
    {
        return false;
    }
}
控制器:

public HttpResponseMessage PostXml([FromBody] XmlDocument xml)
    {//code...}
public HttpResponseMessage Post(XDocument xml)
        {            
            return Request.CreateResponse(HttpStatusCode.OK, xml);
        }

我遵循@Rhot给出的解决方案,但不知何故它不起作用,所以我编辑如下内容,这对我来说是可行的:

public class XmlMediaTypeFormatter : MediaTypeFormatter
    {
        public XmlMediaTypeFormatter()
        {
            SupportedMediaTypes.Add(new MediaTypeHeaderValue("application/xml"));
        }

        public override bool CanReadType(Type type)
        {
            return type == typeof(XDocument);
        }

        public override bool CanWriteType(Type type)
        {
            return type == typeof(XDocument);
        }

        public override Task<object> ReadFromStreamAsync(Type type, Stream stream, HttpContent content, IFormatterLogger formatterLogger)
        {
            var reader = new StreamReader(stream);
            string value = reader.ReadToEnd();            

            var tcs = new TaskCompletionSource<object>();
            try
            {
                var xmlDoc = XDocument.Parse(value);
                tcs.SetResult(xmlDoc);
            }
            catch (Exception ex)
            {
                //disable the exception and create custome error
                //tcs.SetException(ex);
                var xml = new XDocument(
                    new XElement("Error",
                        new XElement("Message", "An error has occurred."),
                        new XElement("ExceptionMessage", ex.Message)
                ));

                tcs.SetResult(xml);
            }

            return tcs.Task;
        }

        public override Task WriteToStreamAsync(Type type, object value, Stream stream, HttpContent content, TransportContext transportContext)
        {
            var writer = new StreamWriter(stream);
            writer.Write(((XDocument)value).ToString());
            writer.Flush();

            var tcs = new TaskCompletionSource<object>();
            tcs.SetResult(null);
            return tcs.Task;
        }              
    }
在我的WebAPI控制器下面:

public HttpResponseMessage PostXml([FromBody] XmlDocument xml)
    {//code...}
public HttpResponseMessage Post(XDocument xml)
        {            
            return Request.CreateResponse(HttpStatusCode.OK, xml);
        }

它不是mvc控制器,而是ApicController,接下来就没有必要添加[HttpPost]属性。此外,在您的示例中,xml也是空的。