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Asp.net 不存在从对象类型System.Web.UI.WebControl.ListItem到已知托管提供程序本机类型的映射_Asp.net - Fatal编程技术网

Asp.net 不存在从对象类型System.Web.UI.WebControl.ListItem到已知托管提供程序本机类型的映射

Asp.net 不存在从对象类型System.Web.UI.WebControl.ListItem到已知托管提供程序本机类型的映射,asp.net,Asp.net,我想我看到了问题: protected void btnsubmit_Click(object sender, EventArgs e) { if (rbtmale.Checked) { gender = "male"; } else if(rbtfemale.Checked) { gender = "female"; } if

我想我看到了问题:

protected void btnsubmit_Click(object sender, EventArgs e)
    {
        if (rbtmale.Checked)
        {
            gender = "male";
        }
        else if(rbtfemale.Checked)
        {
            gender = "female";
        }
        if (cbxsd.Checked)
        {
            designation = "sd";
        }
        else if (cbxasd.Checked)
        {
            designation = "asd";
        }
        else if (cbxtrainee.Checked)
        {
            designation = "trainee";
        }
        if (cbxbsc.Checked)
        {
            qua = "BSc";
        }
        else if (cbxbca.Checked)
        {
            qua = "BCA";
        }
        else if (cbxbtech.Checked)
        {
            qua = "BTech";
        }
        else if (cbxmca.Checked)
        {
            qua = "MCA";
        }
        else if (cbxmba.Checked)
        {
            qua = "MBA";
        }



        SqlConnection con = new SqlConnection(s1);
        SqlCommand cmd = new SqlCommand("sp_2", con);
        cmd.CommandType = CommandType.StoredProcedure;
        con.Open();
        cmd.Parameters.AddWithValue("@id", txtid.Text.Trim());
        cmd.Parameters.AddWithValue("@name",txtname.Text.Trim());
        cmd.Parameters.AddWithValue("@age",txtage.Text.Trim());
        cmd.Parameters.AddWithValue("@sex",gender);
        cmd.Parameters.AddWithValue("@addr",txtaddr.Text.Trim());
        cmd.Parameters.AddWithValue("@hq",qua);
        cmd.Parameters.AddWithValue("@company",ddlcompany.SelectedItem);
        cmd.Parameters.AddWithValue("@desig",designation);
        cmd.Parameters.AddWithValue("@mob",txtmob.Text.Trim());
        cmd.Parameters.AddWithValue("@email", txtemail.Text.Trim());
        cmd.Parameters.Add("@msg", SqlDbType.VarChar, 20).Direction = ParameterDirection.Output;
        cmd.ExecuteNonQuery();
        //if (i > 0)
        //{
        //    Label1.Text = "successfully inserted";
        //}
        //else
        //{
        //    Label1.Text = "failed to insert";
        //}
        string s2 = cmd.Parameters["@msg"].Value.ToString();
        Response.Write(s2);
        con.Close();
    }
应为
ddlcompany.SelectedIndex
ddlcompany.SelectedValue


ddlcompany.SelectedItem引用的是
列表项本身,而不是值。

只需在代码行下方更改此项即可

cmd.Parameters.AddWithValue("@company",ddlcompany.SelectedItem);


它将在SelectedItem需要转换为字符串类型时工作

欢迎使用SO!考虑正确设置问题的格式,以询问特定的问题,并将代码简化为仅存在问题的部分。除非你改进这个问题,否则它肯定会被标记。
cmd.Parameters.AddWithValue("@company",ddlcompany.SelectedItem);
cmd.Parameters.AddWithValue("@company",ddlcompany.SelectedItem.ToString());