Assembly 汇编语言x86 Irvine
我有两项任务:Assembly 汇编语言x86 Irvine,assembly,x86,irvine32,Assembly,X86,Irvine32,我有两项任务: 打印ar2的长度 将元素从ar1移动到ar2,每项递增1 我需要汇编语言x86 IR32的帮助。我必须做上述两件事。我第一个答对了,但第二个我有点迷路了。你是怎么做到的?以下是我目前掌握的情况: INCLUDE Irvine32.inc .data ar1 WORD 1,2,3 ar2 DWORD 3 DUP(?) .code main PROC mov eax, 0 mov eax, LENGTHOF ar2 mov bx, ar1
- 打印
ar2的长度
- 将元素从
移动到ar1
,每项递增1ar2
INCLUDE Irvine32.inc
.data
ar1 WORD 1,2,3
ar2 DWORD 3 DUP(?)
.code
main PROC
mov eax, 0
mov eax, LENGTHOF ar2
mov bx, ar1
mov ebx, ar2
inc ebx
call DumpRegs
exit
main ENDP
END main
您只需从第一个数组中读取单词(每个项目的大小为2),然后将它们复制到包含DWORDs的第二个数组中(每个项目的大小为4): 主进程
mov ecx, LENGTHOF ar2 ; ECX should result in '3'
lea esi, ar1 ; source array - load effective address of ar1
lea edi, ar2 ; destination array - load effective address of ar2
loopECX:
movzx eax, word ptr [esi] ; copies a 16 bit memory location to a 32 bit register extended with zeroes
inc eax ; increases that reg by one
mov dword ptr [edi], eax ; copy the result to a 4 byte memory location
add esi, 2 ; increases WORD array 'ar1' by item size 2
add edi, 4 ; increases DWORD array 'ar2' by item size 4
dec ecx ; decreases item count(ECX)
jnz loopECX ; if item count(ECX) equals zero, pass through
; and ...
call DumpRegs ; ... DumpRegs
exit
main ENDP
END main