Bash 如何搜索和替换多行文字AWK

我有一个包含以下内容的文件（代码片段）——测试可以在文件中的任何位置

More text here
Things-I-DO-NOT-NEED:
      name: "Orange"

      count: 8

      count: 10


Things-I-WANT:
      name: "Apple"

      count: 3

      count: 4

More text here

我想替换：（包括缩进）

与

---

关于使用awk/sed实现这一目标有何建议？谢谢

您可以在awk中执行此操作：

#!/usr/bin/env awk

# Helper variable
{DEFAULT = 1}

# Matches a line that begins with an alphabet
/^[[:alpha:]]+/ { 
    # This matches "Things-I-WANT:"
    if ($0 == "Things-I-WANT:") {
        flag = 1
    }
    # Matches a line that begins with an alphabet and which is 
    # right after "Things-I-WANT:" block
    else if (flag == 1) {
        print "\tname: \"Banana\""
        print ""
        print "\tcount: 7"
        print ""
        flag = 0
    }
    # Matches any other line that begins with an alphabet
    else {
        flag = 0
    }

    print $0
    DEFAULT = 0
}

# If line does not begin with an alphabet, do this
DEFAULT {
    # Print any line that's not within "Things-I-WANT:" block
    if (flag == 0) {
        print $0
    }
}

您可以使用以下命令在

bash

中运行此命令：

$ awk -f test.awk test.txt

此脚本的输出将是：

More text here
Things-I-DO-NOT-NEED:
      name: "Orange"

      count: 8

      count: 10


Things-I-WANT:
    name: "Banana"

    count: 7

More text here

如您所见，

Things-I-WANT:

块已被替换

$ awk -f test.awk test.txt

More text here
Things-I-DO-NOT-NEED:
      name: "Orange"

      count: 8

      count: 10


Things-I-WANT:
    name: "Banana"

    count: 7

More text here