为什么我的while循环不起作用？我正在尝试写一个bash脚本，只要我没有选择第四个循环

这是我的密码 每次我按1，2或3，所以我退出了它的执行，但退出我得到了！永久循环 我做错了什么

echo "Wrhat is your name ! :"
read Name
echo  "Hello $Name ! What would you like me to do ?"
echo "Press 1 to create a note !"
echo "Press 2 to write a text and save it in a note?"
echo "Press 3 to copy your new note ?"
echo "Press 4 to exit ?"
echo $Name >> Note.txt 
read Num
while [[ "$Num" != "4" ]] ; do
    if  [[ $Num = "1" ]]; then
        echo > Note.txt
        echo "Done!"
    elif [[ $Num = "2" ]]; then
        echo "Write your text : "
        read text
        echo $text >> Note.txt
        echo "Done!"
    elif [[ $Num = "3" ]]; then
        cp Note.txt Note1.txt
    else
        exit 0
    fi
done

您需要在每次迭代的循环结束时更新（读取）$Num变量

echo "Wrhat is your name ! :"
read Name
echo  "Hello $Name ! What would you like me to do ?"
echo "Preas 1 to create a note !"
echo "Preas 2 to write a text and save it in a note?"
echo "Preas 3 to copy your new note ?"
echo "Preas 4 to exit ?"
echo $Name >> Note.txt 
read Num
while [[ "$Num" != "" ]] ; do
    if  [[ $Num = "1" ]]; then
        echo > Note.txt
        echo "Done!"
    elif [[ $Num = "2" ]]; then
        echo "Write your text : "
        read text
        echo $text >> Note.txt
        echo "Done!"
    elif [[ $Num = "3" ]]; then
        cp Note.txt Note1.txt
    else
        exit 0
    fi
    read Num
done

---

有一些变化的替代方案：

• 谢邦补充道

• 修正了“你叫什么名字”的输入错误

• 报价为“$Name”

• 集成“while”中的“read Num”

• “case”而不是“if…elif…”

• 关于不需要的输入的错误消息

代码如下：

#!/bin/bash

echo "What is your name ! :"
read Name
echo  "Hello $Name ! What would you like me to do ?"
echo "Press 1 to create a note !"
echo "Press 2 to write a text and save it in a note?"
echo "Press 3 to copy your new note ?"
echo "Press 4 to exit ?"
echo "$Name" >> Note.txt 

while read Num; do
    case "$Num" in

     1) echo > Note.txt
        echo "Done!"
        ;;

     2) echo "Write your text : "
        read text
        echo $text >> Note.txt
        echo "Done!"
        ;;

     3) cp Note.txt Note1.txt
        ;;

     4) break 2
        ;;

     *) echo "Input error"
        ;;
    esac
done

---

Num

从不在循环内部更改，那么为什么您认为循环应该停止？应该如何让它停止？您不需要

“

内部

[[…]]

。移动

读取Num

内部

而[[“$Num”！=“4”]；do

@KhaledMustafa不要忘记这些答案中是否有一个解决了您的问题。或者，最好初始化变量，然后在循环开始处读取。