Bash 如何在linux中使用if条件

当我在终端以任何等级执行此代码时，它总是返回“您的基本值为6000”。这段代码有什么错误？

您需要在=

echo "Enter a grade"
read grade
if test $grade="A"
then
  basic=6000
elif test $grade="B"
then
  basic=5000
else
  basic=4000
fi
echo "Your basic is $basic"

现在，您只需给test命令一个参数，即$grade=“A”，因为空格分隔参数。若您在=，然后测试将有3个参数，即（扩展）$grade，=和“A”

因此：

---

是的，这更接近我自己写的。也可能是“read-p”，即

read-p“输入分数：

。

#!/bin/bash
echo "Enter a grade"
# Read single char
read -n 1 grade
echo $grade
if [ "$grade" == 'A' ]; then
    basic=6000
elif [ "$grade" == 'B' ]; then
    basic=5000
else
    basic=4000
fi
echo "Your basic is $basic"

echo "Enter a grade"
read grade
if test $grade = "A"
then
  basic=6000
elif test $grade = "B"
then
  basic=5000
else
  basic=4000
fi
echo "Your basic is $basic"