Binary 在VHDL中将8位二进制数转换为BCD
该算法是众所周知的,你做8次左移位,并在每次移位后检查单位,10位或数百位(每个4位)。如果他们高于4,你会在小组中增加3,依此类推 这是一个基于流程的解决方案,它不起作用。它将编译,但输出不是我想要的。有什么想法吗?有什么问题吗Binary 在VHDL中将8位二进制数转换为BCD,binary,vhdl,bcd,Binary,Vhdl,Bcd,该算法是众所周知的,你做8次左移位,并在每次移位后检查单位,10位或数百位(每个4位)。如果他们高于4,你会在小组中增加3,依此类推 这是一个基于流程的解决方案,它不起作用。它将编译,但输出不是我想要的。有什么想法吗?有什么问题吗 library ieee ; use ieee.std_logic_1164.all ; use ieee.std_logic_unsigned.all ; entity hex2bcd is port ( hex_in : in std_logic_v
library ieee ;
use ieee.std_logic_1164.all ;
use ieee.std_logic_unsigned.all ;
entity hex2bcd is
port ( hex_in : in std_logic_vector (7 downto 0) ;
bcd_hun : out std_logic_vector (3 downto 0) ;
bcd_ten : out std_logic_vector (3 downto 0) ;
bcd_uni : out std_logic_vector (3 downto 0) ) ;
end hex2bcd ;
architecture arc_hex2bcd of hex2bcd is
begin
process ( hex_in )
variable hex_src : std_logic_vector (7 downto 0) ;
variable bcd : std_logic_vector (11 downto 0) ;
begin
hex_src := hex_in ;
bcd := (others => '0') ;
for i in 0 to 7 loop
bcd := bcd(11 downto 1) & hex_src(7) ; -- shift bcd + 1 new entry
hex_src := hex_src(7 downto 1) & '0' ; -- shift src + pad with 0
if bcd(3 downto 0) > "0100" then
bcd(3 downto 0) := bcd(3 downto 0) + "0011" ;
end if ;
if bcd(7 downto 4) > "0100" then
bcd(7 downto 4) := bcd(7 downto 4) + "0011" ;
end if ;
if bcd(11 downto 8) > "0100" then
bcd(11 downto 8) := bcd(11 downto 8) + "0011" ;
end if ;
end loop ;
bcd_hun <= bcd(11 downto 8) ;
bcd_ten <= bcd(7 downto 4) ;
bcd_uni <= bcd(3 downto 0) ;
end process ;
end arc_hex2bcd ;
ieee库;
使用ieee.std_logic_1164.all;
使用ieee.std_logic_unsigned.all;
实体hex2bcd是
端口(十六进制输入:标准逻辑向量(7到0);
bcd_hun:输出标准逻辑向量(3到0);
bcd十:输出标准逻辑向量(3到0);
bcd_uni:out标准逻辑向量(3到0);
结束hex2bcd;
hex2bcd的架构arc_hex2bcd是
开始
过程(十六进制输入)
变量hex_src:std_逻辑_向量(7到0);
变量bcd:std_逻辑_向量(11到0);
开始
hex_src:=hex_in;
bcd:=(其他=>'0');
对于0到7循环中的i
bcd:=bcd(11向下至1)和hex_src(7);--班次bcd+1新条目
hex_src:=hex_src(从7到1)和“0”;--用0移位src+pad
如果bcd(3向下至0)>“0100”,则
bcd(3向下至0):=bcd(3向下至0)+“0011”;
如果结束;
如果bcd(7至4)>“0100”,则
bcd(7向下至4):=bcd(7向下至4)+“0011”;
如果结束;
如果bcd(11至8)>“0100”,则
bcd(11向下至8):=bcd(11向下至8)+“0011”;
如果结束;
端环;
bcd_hun至少出现两个问题:
- 添加在shift之后完成,而不是在算法中描述的之前
bcd
转换为bcd(11向下转换为1)
,但应为bcd(10向下转换为0)
因此,请尝试以下代码:
process ( hex_in )
variable hex_src : std_logic_vector (7 downto 0) ;
variable bcd : std_logic_vector (11 downto 0) ;
begin
hex_src := hex_in ;
bcd := (others => '0') ;
for i in 0 to 7 loop
if bcd(3 downto 0) > "0100" then
bcd(3 downto 0) := bcd(3 downto 0) + "0011" ;
end if ;
if bcd(7 downto 4) > "0100" then
bcd(7 downto 4) := bcd(7 downto 4) + "0011" ;
end if ;
if bcd(11 downto 8) > "0100" then
bcd(11 downto 8) := bcd(11 downto 8) + "0011" ;
end if ;
bcd := bcd(10 downto 0) & hex_src(7) ; -- shift bcd + 1 new entry
hex_src := hex_src(6 downto 0) & '0' ; -- shift src + pad with 0
end loop ;
bcd_hun <= bcd(11 downto 8) ;
bcd_ten <= bcd(7 downto 4) ;
bcd_uni <= bcd(3 downto 0) ;
end process ;
过程(十六进制)
变量hex_src:std_逻辑_向量(7到0);
变量bcd:std_逻辑_向量(11到0);
开始
hex_src:=hex_in;
bcd:=(其他=>'0');
对于0到7循环中的i
如果bcd(3向下至0)>“0100”,则
bcd(3向下至0):=bcd(3向下至0)+“0011”;
如果结束;
如果bcd(7至4)>“0100”,则
bcd(7向下至4):=bcd(7向下至4)+“0011”;
如果结束;
如果bcd(11至8)>“0100”,则
bcd(11向下至8):=bcd(11向下至8)+“0011”;
如果结束;
bcd:=bcd(10到0)&hex_src(7);--班次bcd+1新条目
hex_src:=hex_src(从6到0)和“0”;--用0移位src+pad
端环;
bcd_hun至少出现两个问题:
- 添加在shift之后完成,而不是在算法中描述的之前
bcd
转换为bcd(11向下转换为1)
,但应为bcd(10向下转换为0)
因此,请尝试以下代码:
process ( hex_in )
variable hex_src : std_logic_vector (7 downto 0) ;
variable bcd : std_logic_vector (11 downto 0) ;
begin
hex_src := hex_in ;
bcd := (others => '0') ;
for i in 0 to 7 loop
if bcd(3 downto 0) > "0100" then
bcd(3 downto 0) := bcd(3 downto 0) + "0011" ;
end if ;
if bcd(7 downto 4) > "0100" then
bcd(7 downto 4) := bcd(7 downto 4) + "0011" ;
end if ;
if bcd(11 downto 8) > "0100" then
bcd(11 downto 8) := bcd(11 downto 8) + "0011" ;
end if ;
bcd := bcd(10 downto 0) & hex_src(7) ; -- shift bcd + 1 new entry
hex_src := hex_src(6 downto 0) & '0' ; -- shift src + pad with 0
end loop ;
bcd_hun <= bcd(11 downto 8) ;
bcd_ten <= bcd(7 downto 4) ;
bcd_uni <= bcd(3 downto 0) ;
end process ;
过程(十六进制)
变量hex_src:std_逻辑_向量(7到0);
变量bcd:std_逻辑_向量(11到0);
开始
hex_src:=hex_in;
bcd:=(其他=>'0');
对于0到7循环中的i
如果bcd(3向下至0)>“0100”,则
bcd(3向下至0):=bcd(3向下至0)+“0011”;
如果结束;
如果bcd(7至4)>“0100”,则
bcd(7向下至4):=bcd(7向下至4)+“0011”;
如果结束;
如果bcd(11至8)>“0100”,则
bcd(11向下至8):=bcd(11向下至8)+“0011”;
如果结束;
bcd:=bcd(10到0)&hex_src(7);--班次bcd+1新条目
hex_src:=hex_src(从6到0)和“0”;--用0移位src+pad
端环;
bcd_hun评论太长了
考虑以下框图:
这表示一个展开的循环(表示0到7循环中的i
),并显示LS BCD数字在i=2之前没有发生add+3,中间BCD数字在i=5之前没有发生add+3,MS BCD数字没有发生调整,这是静态“0”值的一部分
这给我们提供了总共7个add3模块(由封闭的if语句和条件add+3表示)
这在VHDL中得到了演示:
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity bin8bcd is
port (
bin: in std_logic_vector (7 downto 0);
bcd: out std_logic_vector (11 downto 0)
);
end entity;
architecture struct of bin8bcd is
procedure add3 (signal bin: in std_logic_vector (3 downto 0);
signal bcd: out std_logic_vector (3 downto 0)) is
variable is_gt_4: std_logic;
begin
is_gt_4 := bin(3) or (bin(2) and (bin(1) or bin(0)));
if is_gt_4 = '1' then
-- if to_integer(unsigned (bin)) > 4 then
bcd <= std_logic_vector(unsigned(bin) + "0011");
else
bcd <= bin;
end if;
end procedure;
signal U0bin,U1bin,U2bin,U3bin,U4bin,U5bin,U6bin:
std_logic_vector (3 downto 0);
signal U0bcd,U1bcd,U2bcd,U3bcd,U4bcd,U5bcd,U6bcd:
std_logic_vector (3 downto 0);
begin
U0bin <= '0' & bin (7 downto 5);
U1bin <= U0bcd(2 downto 0) & bin(4);
U2bin <= U1bcd(2 downto 0) & bin(3);
U3bin <= U2bcd(2 downto 0) & bin(2);
U4bin <= U3bcd(2 downto 0) & bin(1);
U5bin <= '0' & U0bcd(3) & U1bcd(3) & U2bcd(3);
U6bin <= U5bcd(2 downto 0) & U3bcd(3);
U0: add3(U0bin,U0bcd);
U1: add3(U1bin,U1bcd);
U2: add3(U2bin,U2bcd);
U3: add3(U3bin,U3bcd);
U4: add3(U4bin,U4bcd);
U5: add3(U5bin,U5bcd);
U6: add3(U6bin,U6bcd);
OUTP:
bcd <= '0' & '0' & U5bcd(3) & U6bcd & U4bcd & bin(0);
end architecture;
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity bin8bcd_tb is
end entity;
architecture foo of bin8bcd_tb is
signal bin: std_logic_vector (7 downto 0) := (others => '0');
-- (initialized to prevent those annoying metavalue reports)
signal bcd: std_logic_vector (11 downto 0);
begin
DUT:
entity work.bin8bcd
port map (
bin => bin,
bcd => bcd
);
STIMULUS:
process
begin
for i in 0 to 255 loop
bin <= std_logic_vector(to_unsigned(i,8));
wait for 1 ns;
end loop;
wait for 1 ns;
wait;
end process;
end architecture;
ieee库;
使用ieee.std_logic_1164.all;
使用ieee.numeric_std.all;
实体bin8bcd是
港口(
bin:标准逻辑向量(7到0);
bcd:输出标准逻辑向量(11到0)
);
终端实体;
bin8bcd的体系结构为
程序add3(信号箱:标准逻辑向量中(3至0);
信号bcd:out标准逻辑向量(3到0)为
变量为_gt_4:std_逻辑;
开始
is_gt_4:=第(3)或(第(2)和(第(1)或第(0)条);
如果is_gt_4='1',则
--如果to_integer(unsigned(bin))>4,则
bcd评论太长了
考虑以下框图:
这表示一个展开的循环(表示0到7循环中的i
),并显示LS BCD数字在i=2之前没有发生add+3,中间BCD数字在i=5之前没有发生add+3,MS BCD数字没有发生调整,这是静态“0”值的一部分
这给我们提供了总共7个add3模块(由封闭的if语句和条件add+3表示)
这在VHDL中得到了演示:
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity bin8bcd is
port (
bin: in std_logic_vector (7 downto 0);
bcd: out std_logic_vector (11 downto 0)
);
end entity;
architecture struct of bin8bcd is
procedure add3 (signal bin: in std_logic_vector (3 downto 0);
signal bcd: out std_logic_vector (3 downto 0)) is
variable is_gt_4: std_logic;
begin
is_gt_4 := bin(3) or (bin(2) and (bin(1) or bin(0)));
if is_gt_4 = '1' then
-- if to_integer(unsigned (bin)) > 4 then
bcd <= std_logic_vector(unsigned(bin) + "0011");
else
bcd <= bin;
end if;
end procedure;
signal U0bin,U1bin,U2bin,U3bin,U4bin,U5bin,U6bin:
std_logic_vector (3 downto 0);
signal U0bcd,U1bcd,U2bcd,U3bcd,U4bcd,U5bcd,U6bcd:
std_logic_vector (3 downto 0);
begin
U0bin <= '0' & bin (7 downto 5);
U1bin <= U0bcd(2 downto 0) & bin(4);
U2bin <= U1bcd(2 downto 0) & bin(3);
U3bin <= U2bcd(2 downto 0) & bin(2);
U4bin <= U3bcd(2 downto 0) & bin(1);
U5bin <= '0' & U0bcd(3) & U1bcd(3) & U2bcd(3);
U6bin <= U5bcd(2 downto 0) & U3bcd(3);
U0: add3(U0bin,U0bcd);
U1: add3(U1bin,U1bcd);
U2: add3(U2bin,U2bcd);
U3: add3(U3bin,U3bcd);
U4: add3(U4bin,U4bcd);
U5: add3(U5bin,U5bcd);
U6: add3(U6bin,U6bcd);
OUTP:
bcd <= '0' & '0' & U5bcd(3) & U6bcd & U4bcd & bin(0);
end architecture;
library ieee;
use ieee.std_logic_1164.all;
use ieee.numeric_std.all;
entity bin8bcd_tb is
end entity;
architecture foo of bin8bcd_tb is
signal bin: std_logic_vector (7 downto 0) := (others => '0');
-- (initialized to prevent those annoying metavalue reports)
signal bcd: std_logic_vector (11 downto 0);
begin
DUT:
entity work.bin8bcd
port map (
bin => bin,
bcd => bcd
);
STIMULUS:
process
begin
for i in 0 to 255 loop
bin <= std_logic_vector(to_unsigned(i,8));
wait for 1 ns;
end loop;
wait for 1 ns;
wait;
end process;
end architecture;
ieee库;
使用ieee.std_logic_1164.all;
使用ieee.numeric_std.all;
实体bin8bcd是
港口(
bin:标准逻辑向量(7到0);
bcd:输出标准逻辑向量(11到0)
);
终端实体;
bin8bcd的体系结构为
程序add3(信号箱:标准逻辑向量中(3至0);
信号bcd:out标准逻辑向量(3到0)为
变量为_gt_4:std_逻辑;
开始
is_gt_4:=第(3)或(第(2)和(第(1)或第(0)条);
如果is_gt_4='1',则
--如果to_integer(unsigned(bin))>4,则
bcd1。你需要从bcd的10位到0位来回移动
LIBRARY ieee;
USE ieee.std_logic_1164.ALL;
use ieee.numeric_std.all;
--converting a 8bit binary number to a 12bit bcd
entity bin2bcd is
port (bin :in std_logic_vector (7 downto 0);
bcd1 : out std_logic_vector (3 downto 0);
bcd2 : out std_logic_vector (3 downto 0);
bcd3 : out std_logic_vector (3 downto 0));
end entity;
architecture rtl of bin2bcd is
begin
process ( bin )
variable binx : std_logic_vector (7 downto 0) ;
variable bcd : std_logic_vector (11 downto 0) ;
begin
bcd := (others => '0') ;
binx := bin(7 downto 0) ;
for i in binx'range loop
if bcd(3 downto 0) > "0100" then
bcd(3 downto 0) := std_logic_vector(unsigned( bcd(3 downto 0)) + "0011");
end if ;
if bcd(7 downto 4) > "0100" then
bcd(7 downto 4) := std_logic_vector(unsigned( bcd(7 downto 4)) + "0011");
end if ;
bcd := bcd(10 downto 0) & binx(7) ;
binx := binx(6 downto 0) & '0' ;
end loop ;
bcd3 <= bcd(11 downto 8) ;
bcd2 <= bcd(7 downto 4) ;
bcd1 <= bcd(3 downto 0) ;
end process ;
end architecture;