使用结构和函数时在C中初始化字符数组

我做了一个程序来理解结构的概念和从函数返回struct

struct student
{
    char name[20];
    int age;
    char subject[20];
    int marks;
    int rollno;
}sheet;
struct student display()
{

    sheet.name[20]="Swathi";
    sheet.age=21;
    sheet.subject[20]="Mathematics";
    sheet.marks=85;
    printf("Enter roll no.:");
    scanf("%d",&sheet.rollno);

}
int main()
{   
    struct student sheet1;
    sheet1=display();
    printf("Name:%s",sheet.name);
    printf("Age:%d",sheet.age);

}

我收到两条警告信息

warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  sheet.name[20]="Swathi";
warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  sheet.subject[20]="Mathematics";

为什么会这样？我应该如何改变这个

这里：

sheet.name[20]="Swathi";

只需获取Swathi的只读地址，隐式地将该地址强制转换为一个字符，使其无效，然后将其分配给sheet.name[20]，这超出了范围，因此行为未定义。相反，请尝试以下方法：

strcpy(sheet.name, "Swathi");

同样，sheet.subject[20]=数学；。还要注意，struct student display没有返回任何内容，它应该是void display和struct student sheet1；不需要。

它起作用了

struct student
{
    char name[20];
    int age;
    char subject[20];
    int marks;
    int rollno;
}sheet;
struct student display()
{

    strcpy(sheet.name, "Swathi");
    sheet.age=21;
    strcpy(sheet.subject,"Mathematics");
    sheet.marks=85;
    printf("Enter roll no.:");
    scanf("%d",&sheet.rollno);

}
int main()
{   
    display();
    printf("Name:%s",sheet.name);
    printf("Age:%d",sheet.age);

}

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