Char从“Char*”到“Char”[-fpermissive]的转换无效

我在从“char*”到“char”[-fppermissive]的无效转换中遇到问题。 在这里，我将数据移动一位

char text[]="5052.4318" ,temp; 

当我这样写的时候，好的，它正在工作，但是我需要从数组中读取数据[3]。 我如何处理这个问题

#include <iostream>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main ()
{
    char *array[3];

    array[3]="5052.4318";
    char text[]={array[3]} ,temp; 
    int text_len = strlen (text),i;
    for (i =0; i <=text_len - 1; i++)
    {
        if (text[i] == '.')
        {
                temp = text[i-1];
                text[i-1] = text[i];
                text[i] = temp;
        }
    }

    printf ("%s\n", text); 
    return 0;
}

5052.43525是纬度值。首先我需要像这样移动数据50.5243525。在除以数字60=>52.43525/60=0.87392083之后再次移动>>。 所以结果应该是50.87392083。另一个问题是我不应该对字符串使用atof命令来浮动值。因为我使用的是Coocox，没有在调试中工作。也许我需要使用null终端。我正在分享我正在做的代码

  #include <stdio.h>
 #include <string.h>
 #include <stdlib.h>
 int main ()
 {
//char buf[] 
="$GPRMC,121212,A,4807.038,N,01131.000,E,022.4,084.4,030611,003.1,W*6A";

char T[100];
sprintf(T, 
"%s","$GPRMC,093612.000,A,5052.43525,N,00440.11204,E,0.0,0.0,130917,,,A*6C");
printf(T);
char *buf[]={T};
int i = 0;
char *p = strtok (*buf, ",");
char *array[12];

while (p !=0)
{
    array[i++] = p;
    p = strtok (0, ",");

}

for (i = 0; i < 11; ++i) {
array[i];
 printf("%s\n",array[i]);
 }
 //char *array[3] = {"5052.4318"};
size_t text_len = strlen(array[3]);
char text[text_len +1], temp;
int i1;
    strcpy(text, array[3]);
for (i1 =0; i1 <=text_len - 1; i1++)
{
    if (text[i1] == '.')
    {
            temp = text[i1-1];
            text[i1-1] = text[i1];
            text[i1] = temp;
    }
}
    for (i1 =0; i1 <=text_len - 1; i1++)
{
    if (text[i1] == '.')
    {
            temp = text[i1-1];
            text[i1-1] = text[i1];
            text[i1] = temp;
    }
 }
 char *buf1[]={text};
 int i3 = 0;
 char *p1 = strtok (*buf1, ".");
 char *array1[2];

  while (p1 !=0)
  {
    array1[i3++] = p1;
    p1 = strtok (0, ".");

 }

 for (i3 = 0; i3 < 2; ++i3) {
 array1[i3];
 } double d;
 float m;
 int k=0;

 d= (atof(array1[1])/6000);
 char s[1]= {d};
 m=(atof(array1[0]));
 printf("%f\n",m);
 printf("%lf\n",d);


return 0;

}

结果应为50.87392083。 我还没有完成

---

谢谢

我不完全确定您想要实现什么，但是您的代码的第一部分有一些问题。您的初始化行实际上不正确

我想你是想把你的字符串除以10。保留您的算法，我已经修复了一些问题，并对其进行了编译

// #include <iostream> // This is C not C++. Also you include stdio.h...
#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main ()
{
    char array[] = "5052.4318"; // This initialization 
                                // one of your errors
    char * text = array + 3; // I don't know why you are pointing 
                             // fourth element of the array, but you may do
                             // in this way

    // Let's say I prefer to start from the starting of 
    // the array
    text = array;

    printf ("%s\n", text);

    int text_len = strlen(text);
    for (int i = 1; i <= text_len - 1; i++) { // You will have some problem 
                                              // if you start from 0...
      if (text[i] == '.') {
        char temp; // temp is used only here, so let's define it in the
                   // only scope that needs it.
        temp = text[i - 1]; // This -1 is the reason why you may start
                            // the for from 1, instead of 0.
        text[i - 1] = text[i];
        text[i] = temp;
      }
    }

    printf ("%s\n", text); 
    return 0;
}

这就是你想要实现的吗

for从1开始处理字符串，如.1234

也是：一个控制C++编译器的方言的标志。这不是你在C.编译时看到的东西，因为你包含了IOSROW，编译器自动切换到C++编译器。在这件事上你必须非常小心

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main ()
{
    char text[30]="5052.4318",temp;
    int text_len = strlen (text),i;
    //printf("%s\n%d\n",text,text_len);
    for (i =0; i <=text_len - 1; i++)
    {
        if (text[i] == '.')
        {
                temp = text[i-1];
                text[i-1] = text[i];
                text[i] = temp;
        }
    }

    printf ("%s\n", text);
    return 0;
}

---

您不需要使用额外的字符数组来实现所需的结果。

我很惊讶，这是您显示的代码的唯一问题。数组初始值设定项必须是编译时常量。您不能像使用文本一样使用运行时变量初始化数组。此外，当您使用数组[3]=5052.4318时，您的索引超出了范围！数组中的最后一个索引是2。数组是指针数组，数组[3]超出范围。您也不能将5052.4318分配给char*，应改为malloc和strcpy.char*数组[1]；数组[0]=5052.4318；这是给，也是同样的错误，我用strcpy，但没有工作。我要试试马洛克@葛哈德：是的，这实际上是一个问题，但问题是OP想要改变文字，所以它不起作用。

// #include <iostream> // This is C not C++. Also you include stdio.h...
#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main ()
{
    char array[] = "5052.4318"; // This initialization 
                                // one of your errors
    char * text = array + 3; // I don't know why you are pointing 
                             // fourth element of the array, but you may do
                             // in this way

    // Let's say I prefer to start from the starting of 
    // the array
    text = array;

    printf ("%s\n", text);

    int text_len = strlen(text);
    for (int i = 1; i <= text_len - 1; i++) { // You will have some problem 
                                              // if you start from 0...
      if (text[i] == '.') {
        char temp; // temp is used only here, so let's define it in the
                   // only scope that needs it.
        temp = text[i - 1]; // This -1 is the reason why you may start
                            // the for from 1, instead of 0.
        text[i - 1] = text[i];
        text[i] = temp;
      }
    }

    printf ("%s\n", text); 
    return 0;
}

5052.4318
505.24318

#include <stdio.h>
#include <string.h>
#include <stdlib.h>

int main ()
{
    char text[30]="5052.4318",temp;
    int text_len = strlen (text),i;
    //printf("%s\n%d\n",text,text_len);
    for (i =0; i <=text_len - 1; i++)
    {
        if (text[i] == '.')
        {
                temp = text[i-1];
                text[i-1] = text[i];
                text[i] = temp;
        }
    }

    printf ("%s\n", text);
    return 0;
}