使用sscanf进行解析不会';t保存数组以供后续使用
我正在从事一个项目,该项目模拟一个n路关联缓存映射。然而,当试图在后续等式中使用地址[i]数组时,问题就出现了。我想我不明白为什么数组没有被保存。任何帮助都将不胜感激。我不是C代码的高手。现在的问题是读取文件并将这些值扫描到数组中。其他我有信心的事情我都能弄明白 代码如下:使用sscanf进行解析不会';t保存数组以供后续使用,c,arrays,parsing,fgets,scanf,C,Arrays,Parsing,Fgets,Scanf,我正在从事一个项目,该项目模拟一个n路关联缓存映射。然而,当试图在后续等式中使用地址[i]数组时,问题就出现了。我想我不明白为什么数组没有被保存。任何帮助都将不胜感激。我不是C代码的高手。现在的问题是读取文件并将这些值扫描到数组中。其他我有信心的事情我都能弄明白 代码如下: #include <stdio.h> #include <stdlib.h> #include <string.h> #include <math.h> /*global
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <math.h>
/*global variables */
int mainSize, cacheSize, blockSize, cmSet, cnumBlocks, mnumBlocks,address[50],mmBlkNum[50], mappedCMset[50],hit_miss[50],address[50];
char mode[50];
int totMemRefs=0;
int main(void)
{
/*Variables */
int i;
char replacePolicy;
char filename[50];
char *result = NULL;
char line[50];
FILE *fp;
fp = fopen(filename, "r");
/*Gathers input from user */
printf("Enter the main memory size between between 4 and 32K bytes: ");
scanf("%d",&mainSize);
if (mainSize < 4 || mainSize > 32768)
{
printf("Invalid main memory size.");
//errorCheck()
}
printf("Enter the size of the cache between 2 and 32K bytes: ");
scanf("%d", &cacheSize);
if (cacheSize < 2 || cacheSize > 32768)
{
printf("Invalid cache memory size.");
//errorCheck()
}
printf("Enter the size of the block/line between 2 and 32K bytes: ");
scanf("%d",&blockSize);
if (blockSize < 2 || blockSize > 32768)
{
printf("Invalid block/line size.");
//errorCheck
}
printf("Enter the degree of set-associativity: ");
scanf("%d", &cmSet);
cnumBlocks = cacheSize/blockSize;
printf("Number of blocks in cache = %d\n", cnumBlocks);
mnumBlocks = mainSize/blockSize;
printf("Number of blocks in main memory = %d\n", mnumBlocks);
printf("Enter replacement policy (L = LRU, F = FIFO): ");
scanf("%s", &replacePolicy);
printf("Enter the name of the file containing the list of memory referenced: ");
scanf("%s", filename);
/* checks if filename is valid/exits */
if ((fp = fopen(filename, "r")) == NULL)
{
printf("Invalid input.");
//errorCheck();
}
/* gets total number of mem references from first line of file and stores in variable totMemRefs*/
fgets(line,sizeof(line),fp);
result = strtok(line,"\n");
totMemRefs = atoi(result);
printf("Total Mem Refs = %d\n", totMemRefs);
/*skips second line of white space */
fgets(line, sizeof(line),fp);
i=0;
//reads each line of file and tokenizes into mode and address
while (fgets(line, sizeof(line), fp)!=NULL)
{
if (sscanf(line,"%s %d",&mode[i],&address[i]) == 2)
{
printf("Mode: %c Address: %d\n",mode[i],address[i]);
i++;
}
}//end of parsing while loop
fclose(fp); //close file after reading
for (i=0; i<totMemRefs; i++)
{
/* calculates the corresponding block number of the address */
mmBlkNum[i]=address[i]/blockSize;
/* calculates the corresponding cache mem set that mm block is in */
mappedCMset[i]=mmBlkNum[i]%cnumBlocks;
printf("Mode = %c Address = %d MM Block Num = %d Cm Set = %d\n", mode[i],address[i],mmBlkNum[i],mappedCMset[i]);
}
}//end of main
以下是主存储器和高速缓存的特征:
main mem size = 128 bytes
cache mem size = 32 bytes
block size = 4 bytes
set associativity = 2
filename = example_test_data.txt
这是while循环中阵列的输出:
Mode: R Address: 0
Mode: R Address: 1
Mode: R Address: 4
Mode: R Address: 36
Mode: R Address: 0
Mode: R Address: 4
这是解析后数组的输出——在以下for循环中:
Mode = R Address = 4 MM Block Num = 1 Cm Set = 1
Mode = Address = 0 MM Block Num = 0 Cm Set = 0
Mode = Address = 0 MM Block Num = 0 Cm Set = 0
Mode = Address = 0 MM Block Num = 0 Cm Set = 0
Mode = Address = 0 MM Block Num = 0 Cm Set = 0
Mode = Address = 0 MM Block Num = 0 Cm Set = 0
如您所见,模式和地址数组的第二次迭代与文件while循环中的不同。我不明白为什么会这样。我尽量用描述性的语言。我也不知道为什么格式没有出现。很抱歉,这会让你更难阅读。再次重申,任何帮助或推动正确的方向将不胜感激
编辑:
输出应为:
Mode = R Address = 0 MM Blk Num = 0 CM Set = 0
Mode = R Address = 1 MM Blk Num = 0 CM Set = 0
Mode = R Address = 4 MM Blk Num = 1 CM Set = 1
Mode = R Address = 36 MM Blk Num = 9 CM Set = 1
Mode = R Address = 0 MM Blk Num = 0 CM Set = 0
Mode = R Address = 4 MM Blk Num = 1 CM Set = 1
我知道得到正确值所需的方程式。我知道怎么用手做这些没问题。因此,知道结果应该是什么并不是问题。
在此之前,我使用了fscanf和strtok,但它们都没有产生预期的结果。基本上,当我在扫描时在while循环中打印它时,它可以工作,但是一旦我尝试计算mmBlkNum和mappedCMset,数组中的值就不一样了
代码已更新 我看到的第一个错误:
scanf("%s", &filename);
替换为正确的参数:
scanf("%s", filename);
请使用-Wall
进行编译,这样编译器就会说这些话。与-Werror
结合使用<代码>-也建议使用Wextra
我的编译器输出与您的程序:
stackoverflow.c: In function 'main':
stackoverflow.c:246:11: error: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Werror=format=]
scanf("%s", &filename);
^
cc1.exe: all warnings being treated as errors
我看到的第二个错误是:在while
循环中,您将所有读取的内容都放在同一个索引I=0
。为使用,或在
时正确使用:
i = 0;
while (fgets(line, sizeof(line), fp)!=NULL && i < totMemRefs)
{
if (sscanf(line,"%s %d",&mode[i],&address[i]) == 2)
{
printf("Mode: %c Address: %d\n",mode[i],address[i]);
i++;
}
}//end of parsing while loop
if (i < totMemRefs)
{
fprintf(stderr, "Missing inputs.\n");
return 1;
}
使用MAX\u INPUT\u LINES
而不是50
你需要做一些工作才能找到一个新的方法。没有人会看你的代码墙。在找出显示您的问题的最小完整示例时,您不仅可以帮助我们,而且很有可能您自己也会发现问题。@davidbak我花了几天时间试图找出问题以及实现目标的不同方法,但仍然无济于事。我知道代码应该做什么,并且我添加了一个正确输出的示例,但是我没有看到问题所在。尽管如此,还是要感谢你的评论。我要说的是与戴维贝克相反的话。代码不是很长,但它不是一个完整且可验证的示例。请提供一个完整的编译程序,并对其进行测试,以确保它能产生您指定输入的输出(有时人们会删除代码以使其变小,并发布一个程序,在他们的问题中没有任何错误)。@jdarthenay我在中添加了其余的代码。它在我的系统上编译。错误:格式'%s'要求参数类型为'char*',但参数2的类型为'char(*)[50]'[-Werror=format=]
虽然由于我的声誉不高,我无法对你的答案投赞成票,但我衷心感谢你花时间仔细阅读我的代码@jdarthenay我对C没有太多的经验,但是在愿意花一点时间的人们的帮助下,我正在学习!!再次感谢你@如果我的答案解决了你的问题,你应该接受它,它应该在低于我答案分数的地方。
i = 0;
while (fgets(line, sizeof(line), fp)!=NULL && i < totMemRefs)
{
if (sscanf(line,"%s %d",&mode[i],&address[i]) == 2)
{
printf("Mode: %c Address: %d\n",mode[i],address[i]);
i++;
}
}//end of parsing while loop
if (i < totMemRefs)
{
fprintf(stderr, "Missing inputs.\n");
return 1;
}
#define MAX_INPUT_LINES 50