如何在C中仅反转整数（32位）的最后8位？

我已经用C实现了下面的函数，但它不能正常工作

int reverse(int org_num){
   int rev_num=0;
   int i=1;
   while(i<=8){
       int last_bit=org_num&1;
       rev_num=rev_num|last_bit;
       rev_num=rev_num<<1;
       org_num=org_num>>1;

       i=i+1;
   }
   return rev_num; }

---

您可以这样做来可视化代码正在执行的操作

void printBin(int num)
{
    const int N = 8;
    for (int i = 0; i < 8; ++i)
    {
        cout << ((num >> i) & 1);
    }
    cout << "\n";
}

void reverse(int org_num) {
    printBin(org_num);

    bool bit_back = 0;
    bool bit_front = 0;

    for (int i = 0, j = 7; i < 4; ++i, --j)
    {
        // obtaining the bits
        bit_back = (org_num >> i) & 1;
        bit_front = (org_num >> j) & 1;
        // zeroing out the bits
        org_num ^= (bit_front << j);
        org_num ^= (bit_back << i);
        // inserting the bits
        org_num |= (bit_back << j);
        org_num |= (bit_front << i);
    }

    printBin(org_num);
}

---

输入73，它给出146，这是我想要的；但是有146个，它就有72个，这显然是不对的，没关系！我得到了它。上次我不需要把倒过来的号码右移。