Coffeescript 将条件调用和函数调用放在一行中
有没有一种方法(希望是干净的)可以在这里做同样的事情,而不必指定状态值? 当if条件位于同一行时,我一直遇到if条件返回布尔值(而不是函数)的问题Coffeescript 将条件调用和函数调用放在一行中,coffeescript,Coffeescript,有没有一种方法(希望是干净的)可以在这里做同样的事情,而不必指定状态值? 当if条件位于同一行时,我一直遇到if条件返回布尔值(而不是函数)的问题 onItemChanged = (event,ui) -> input_element = event.target list_id = input_element.getAttribute('list_id') state = if input_element.checked onItemChecked /
onItemChanged = (event,ui) ->
input_element = event.target
list_id = input_element.getAttribute('list_id')
state = if input_element.checked
onItemChecked //function of int -> nothing
else
onItemUnchecked //function of int -> nothing
state (list_id )
不确定你是否认为它更干净,但是你也可以直接调用<代码>的结果,如果表达式直接:
onItemChanged = (event,ui) ->
input_element = event.target
list_id = input_element.getAttribute('list_id')
(if input_element.checked then onItemChecked else onItemUnchecked) list_id
或者只需调用中的onItemChecked
或onItemUnchecked
,如果
:
onItemChanged = (event,ui) ->
input_element = event.target
list_id = input_element.getAttribute('list_id')
if input_element.checked
onItemChecked list_id
else
onItemUnchecked list_id
不确定你是否认为它更干净,但是你也可以直接调用<代码>的结果,如果表达式直接:
onItemChanged = (event,ui) ->
input_element = event.target
list_id = input_element.getAttribute('list_id')
(if input_element.checked then onItemChecked else onItemUnchecked) list_id
或者只需调用中的onItemChecked
或onItemUnchecked
,如果
:
onItemChanged = (event,ui) ->
input_element = event.target
list_id = input_element.getAttribute('list_id')
if input_element.checked
onItemChecked list_id
else
onItemUnchecked list_id
像这样:
onItemChanged = (event, ui) ->
input = event.target
state = if input.checked then onItemChecked else onItemUnchecked
state input.getAttribute('list_id')
甚至:
onItemChanged = ({target: input}, ui) ->
state = if input.checked then onItemChecked else onItemUnchecked
state input.getAttribute('list_id')
像这样:
onItemChanged = (event, ui) ->
input = event.target
state = if input.checked then onItemChecked else onItemUnchecked
state input.getAttribute('list_id')
甚至:
onItemChanged = ({target: input}, ui) ->
state = if input.checked then onItemChecked else onItemUnchecked
state input.getAttribute('list_id')