C++ Break语句不在循环或开关语句中？

我的代码有问题，我读过这个网站的其他论坛关于这个问题，但它们与我的情况并不相关。我是新来的C++，我几乎没有3周的课程。我不知道为什么我的break语句不起作用，对我来说它在循环中。我错过了什么

float a[60][7];
int row;
cout << "How many students would you like to grade?" << endl;

cin >> studentNum;

cout << "Enter grades for the first student" << endl;

row = 0;
n = studentNum - 2;

while (row < studentNum)
{
    a[row][0]=k;
    a[row][0] = row;
    cout << "Enter grade for test 1: ";
    cin >> a[row][1];
    cout << "Enter grade for test 2: ";
    cin >> a[row][2];
    cout << "Enter grade for test 3: ";
    cin >> a[row][3];
    cout << "Enter grade for test 4: ";
    cin >> a[row][4];



    a[row][5] = (a[row][1] + a[row][2] + a[row][3] + a[row][4]) / 4;
    a[row][6] = a[row][1] * 0.2 + a[row][2] * 0.3 + a[row][3] * 0.3 + a[row][4] * 0.2;

    row++;
}
if (row == n)
{
    cout << "Enter Grades for the last Student" << endl;
    cout << "Enter grade for test 1: ";
    cin >> a[row][1];
    cout << "Enter grade for test 2: ";
    cin >> a[row][2];
    cout << "Enter grade for test 3: ";
    cin >> a[row][3];
    cout << "Enter grade for test 4: ";
    cin >> a[row][4];
    break;
}
else
{ 
   cout << "Enter grades for the next student" << endl;
   row = row + 1;
}



cout << "Stdnt" << "\t" << "Grade1" << "\t" << "Grade2" << "\t" << "Grade3" << "\t" << "Grade4" << "\t" << "Avg1" << "\t" << "Avg2" << endl;
printarray(a, studentNum);

cin.get();
return 0;

float a[60][7]；
int行；
学生人数；
cout a[行][2]；
cout>a[行][3]；
cout>a[行][4]；
[行][5]=（a[行][1]+a[行][2]+a[行][3]+a[行][4]）/4；
[行][6]=a[行][1]*0.2+a[行][2]*0.3+a[行][3]*0.3+a[行][4]*0.2；
行++；
}
如果（行==n）
{
cout a[行][2]；
cout>a[行][3]；
cout>a[行][4]；
打破
}
其他的
{ 
难道不能这样吗

float a[60][7];
int row = 0;

std::cout << "How many students would you like to grade?" << std::endl;
std::cin >> studentNum;

n = studentNum - 2;

std::cout << "Enter grades for the first student" << std::endl;
while (row <= n)
{
  a[row][0] = k;
  a[row][0] = row;
  std::cout << "Enter grade for test 1: ";
  std::cin >> a[row][1];
  std::cout << "Enter grade for test 2: ";
  std::cin >> a[row][2];
  std::cout << "Enter grade for test 3: ";
  std::cin >> a[row][3];
  std::cout << "Enter grade for test 4: ";
  std::cin >> a[row][4];


  a[row][5] = (a[row][1] + a[row][2] + a[row][3] + a[row][4]) / 4;
  a[row][6] = a[row][1] * 0.2 + a[row][2] * 0.3 + a[row][3] * 0.3 + a[row][4] * 0.2;

  if (row==n)
  {
    std::cout << "Enter Grades for the last Student" << std::endl;
    std::cout << "Enter grade for test 1: ";
    std::cin >> a[row][1];
    std::cout << "Enter grade for test 2: ";
    std::cin >> a[row][2];
    std::cout << "Enter grade for test 3: ";
    std::cin >> a[row][3];
    std::cout << "Enter grade for test 4: ";
    std::cin >> a[row][4];
  }
  else
  { 
    std::cout << "Enter grades for the next student" << std::endl;
  }

  row++;
}

std::cout << "Student" << "\t" << "Grade1" << "\t" << "Grade2" << "\t" << "Grade3" << "\t" << "Grade4" << "\t" << "Avg1" << "\t" << "Avg2" << std::endl;
printarray(a, studentNum);

std::cin.get();
return 0;

float a[60][7]；
int行=0；
std：：cout studentNum；
n=studentNum-2；
标准：：cout a[行][3]；
标准：：cout>a[行][4]；
[行][5]=（a[行][1]+a[行][2]+a[行][3]+a[行][4]）/4；
[行][6]=a[行][1]*0.2+a[行][2]*0.3+a[行][3]*0.3+a[行][4]*0.2；
如果（行==n）
{
标准：：cout a[行][2]；
标准：：cout>a[行][3]；
标准：：cout>a[行][4]；
}
其他的
{ 
std：：cout你想通过
结尾的
中断
实现什么？如果
真的很感谢你的帮助，我正在网上学习这门课程以获得成功，但我知道这是一个错误，我的教授不会回复我的电子邮件：（@Michael我想要“为最后一个学生输入分数”的声明）以最后一个学生结束评分。但是现在，当我运行程序时，“为最后一个学生输入分数”甚至不会弹出“为最后一个学生输入分数”出现在程序的最底部，您可能需要在
while
循环中移动
if
和
else
，设置
while（行是！非常感谢：）@MichaelRemove else子句中的额外行+。