C++ N-Queens解决方案C++;
所以我需要帮助解决经典的N皇后问题 运行程序的命令为: nqueens N k-其中N是表格的大小(N x N),k是解决方案的数量 因此,例如,如果我要通过键入nqueens41来运行程序,则会打印出以下内容 _Q__ __uq Q_uu_u_ __Q_ 但是,我不知道如何处理多个解决方案?如何确定此问题的多个解决方案 到目前为止,我掌握的情况如下:C++ N-Queens解决方案C++;,c++,n-queens,C++,N Queens,所以我需要帮助解决经典的N皇后问题 运行程序的命令为: nqueens N k-其中N是表格的大小(N x N),k是解决方案的数量 因此,例如,如果我要通过键入nqueens41来运行程序,则会打印出以下内容 _Q__ __uq Q_uu_u_ __Q_ 但是,我不知道如何处理多个解决方案?如何确定此问题的多个解决方案 到目前为止,我掌握的情况如下: #include <cstdlib> #include <iomanip> #include <cmath>
#include <cstdlib>
#include <iomanip>
#include <cmath>
#include <vector>
using namespace std;
class Board
{
private:
bool** spaces;
int size;
public:
Board(int size)
{
this->size = size;
spaces = new bool*[size];
for (int i = 0; i < size; ++i)
{
spaces[i] = new bool[size];
}
}
bool isSafe(int row, int column, vector<int>& state)
{
//check row conflict
//no need to check for column conflicts
//because the board is beimg filled column
//by column
for(int i = 0; i < column; ++i)
{
if(state[i] == row)
return false;
}
//check for diagonal conflicts
int columnDiff = 0;
int rowDiff = 0;
for(int i = 0; i < column; ++i)
{
columnDiff = abs(column - i);
rowDiff = abs(row - state[i]);
if(columnDiff == rowDiff)
return false;
}
return true;
}
int getSize()
{
return size;
}
bool getSpace(int x, int y)
{
return spaces[y][x];
}
void setSpace(int x, int y, bool value)
{
spaces[y][x] = value;
}
Board(Board& other)
{
this->size = other.getSize();
spaces = new bool*[size];
for (int i = 0; i < size; ++i)
{
spaces[i] = new bool[size];
for (int j = 0; j < size; ++j)
{
spaces[i][j] = other.getSpace(j, i);
}
}
}
void backtrack(vector<int>& state, int board_size)
{
int row = 0;
int column = 0;
bool backtrack = false;
while(column < board_size)
{
while(row < board_size)
{
if(backtrack)
{
row = state[column] + 1;
if(row == board_size)
{
column--; //backtrack more
backtrack = true;
row = 0;
break;
}
backtrack = false;
}
if(isSafe(row, column, state))
{
state[column] = row;
row = 0;
column++; //advance
backtrack = false;
break;
}
else
{
if(row == (board_size - 1))
{
column--; //backtrack
backtrack = true;
row = 0;
}
else
{
row++;
}
}
}
}
}
};
int print_solutions(Board *board, vector<int>& state, int board_size)
{
for(int i=0; i < board_size; ++i)
{
for(int j=0; j < board_size; ++j)
{
if(state[i] == j)
cout << 'Q' << " ";
else
cout << '_' << " ";
}
cout << endl;
}
}
int main(int argc, char* argv[])
{
if (argc < 2)
{
cout << "Usage: nqueens [Board Size] [Number of Solutions]" << endl;
return 1;
}
int board_size = atoi(argv[1]);
//int solution_count = atoi(argv[2]);
vector<int> state;
state.resize(board_size);
Board *my_board = new Board(board_size);
my_board->backtrack(state, board_size);
print_solutions(my_board, state, board_size);
return 0;
}
#包括
#包括
#包括
#包括
使用名称空间std;
班级委员会
{
私人:
布尔**空间;
整数大小;
公众:
电路板(内部尺寸)
{
这个->大小=大小;
空格=新布尔*[大小];
对于(int i=0;isize=other.getSize();
空格=新布尔*[大小];
对于(int i=0;i cout在这个解决方案中,我保留了大部分原始方法和代码:
#include <cstdlib>
#include <iomanip>
#include <cmath>
#include <vector>
#include <iostream>
using namespace std;
class Board
{
private:
bool** spaces;
int size;
public:
Board(int size)
{
this->size = size;
spaces = new bool*[size];
for (int i = 0; i < size; ++i)
{
spaces[i] = new bool[size];
}
}
bool isSafe(int row, int column, vector<int>& state)
{
//check row conflict
//no need to check for column conflicts
//because the board is beimg filled column
//by column
for(int i = 0; i < column; ++i)
{
if(state[i] == row)
return false;
}
//check for diagonal conflicts
int columnDiff = 0;
int rowDiff = 0;
for(int i = 0; i < column; ++i)
{
columnDiff = abs(column - i);
rowDiff = abs(row - state[i]);
if(columnDiff == rowDiff)
return false;
}
return true;
}
int getSize()
{
return size;
}
bool getSpace(int x, int y)
{
return spaces[y][x];
}
void setSpace(int x, int y, bool value)
{
spaces[y][x] = value;
}
Board(Board& other)
{
this->size = other.getSize();
spaces = new bool*[size];
for (int i = 0; i < size; ++i)
{
spaces[i] = new bool[size];
for (int j = 0; j < size; ++j)
{
spaces[i][j] = other.getSpace(j, i);
}
}
}
bool backtrack(vector<int>& state, int& column, int board_size)
{
int row = 0;
bool backtrack = column == board_size;
while(column < board_size || backtrack)
{
{
if(backtrack)
{
if (column == 0)
return false;
column--;
row = state[column] + 1;
if(row == board_size)
{
backtrack = true;
continue;
}
backtrack = false;
}
if(isSafe(row, column, state))
{
state[column] = row;
row = 0;
column++; //advance
backtrack = false;
continue;
}
else
{
if(row == (board_size - 1))
{
backtrack = true;
}
else
{
row++;
}
}
}
}
return true;
}
};
void print_solutions(Board *board, vector<int>& state, int board_size)
{
for(int i=0; i < board_size; ++i)
{
for(int j=0; j < board_size; ++j)
{
if(state[i] == j)
cout << 'Q' << " ";
else
cout << '_' << " ";
}
cout << endl;
}
cout << endl;
}
int main(int argc, char* argv[])
{
if (argc < 3)
{
cout << "Usage: nqueens [Board Size] [Number of Solutions]" << endl;
return 1;
}
int board_size = atoi(argv[1]);
int solution_count = atoi(argv[2]);
vector<int> state;
state.resize(board_size);
Board *my_board = new Board(board_size);
int column = 0;
while (solution_count-- > 0 && my_board->backtrack(state, column, board_size))
print_solutions(my_board, state, board_size);
return 0;
}
#包括
#包括
#包括
#包括
#包括
使用名称空间std;
班级委员会
{
私人:
布尔**空间;
整数大小;
公众:
电路板(内部尺寸)
{
这个->大小=大小;
空格=新布尔*[大小];
对于(int i=0;isize=other.getSize();
空格=新布尔*[大小];
对于(int i=0;i#include<vector>
using namespace std;
bool intersect(const vector<int> &queens, int x) {
int y = queens.size();
for (int i = 0; i < y; i++) {
if ((abs(queens[i] - x) == 0) || (abs(queens[i] - x) == y - i))
return true;
}
return false;
}
void queensSolution(const int dim, vector<int> queens, vector<vector<int>> &res) {
if (queens.size() >= dim) {
res.push_back(queens);
queens.clear();
return;
}
for (int i = 0; i < dim; i++) {
if (!intersect(queens, i)) {
queens.push_back(i);
queensSolution(dim, queens, res);
queens.pop_back();
}
}
}
int main(){
int dim = 4;
vector<int>queens;
vector<vector<int>> result;
queensSolution(dim, queens, result);
}