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C++ 枚举Qt C+中的QML属性+;?_C++_Qt_Qml_Qtcore_Qmetaobject - Fatal编程技术网

C++ 枚举Qt C+中的QML属性+;?

C++ 枚举Qt C+中的QML属性+;?,c++,qt,qml,qtcore,qmetaobject,C++,Qt,Qml,Qtcore,Qmetaobject,我正在执行以下操作以在我的Qt嵌入式应用程序中呈现QML: QDeclarativeView *view = new QDeclarativeView(this); view->setSource(QUrl::fromLocalFile("dial.qml")); view->show(); QObject *dial = view->rootObject(); 是否有一种方法可以枚举根项中定义的所有属性值 例如,如果我有QML: import QtQuick 1.0 Ite

我正在执行以下操作以在我的Qt嵌入式应用程序中呈现QML:

QDeclarativeView *view = new QDeclarativeView(this);
view->setSource(QUrl::fromLocalFile("dial.qml"));
view->show();
QObject *dial = view->rootObject();
是否有一种方法可以枚举根项中定义的所有属性值

例如,如果我有QML:

import QtQuick 1.0
Item {
  id: root
  property real dial_value : 0
  property real dial_length: 0
  property real background_opacity: 1
  etc, etc
}
有没有一个Qt方法最终会让我得到这些字符串的列表:

dial_value
dial_length
background_opacity
我试过了,但列表是空的:

QList<QByteArray> list = dial->dynamicPropertyNames();
QList list=dial->dynamicPropertyNames();
提前谢谢

你可以写:

for (int i = 0; i < dial->metaObject->propertyCount(); ++i) {
    QMetaProperty metaProperty = dial->metaobject()->property(i);
    qDebug() << metaProperty.name();
}
for(int i=0;imetaObject->propertyCount();++i){
QMetaProperty metaProperty=dial->metaobject()->property(i);

qDebug()您是否尝试过拨号->元对象->属性(索引);在一个循环中使用propertyCount()方法,然后使用name()方法?这样就可以了!谢谢:)