在文本文件C++中保存排序元素

我有一个冒泡排序程序，用升序排序数组

如何将排序后的元素保存在文本文件中，并每隔一个数字（例如-1、0、1、2、3、4）加上逗号

文本文件中是已排序的元素-1,0,1,2,3,4

#include<iostream>
#include<fstream>
using namespace std;

int compare (int, int);
void sort(int[], const int);
int compare(int x, int y){
    return(x > y);
}
void swap(int *x, int *y){
    int temp;
    temp = *x;
    *x = *y;
    *y = temp;
}
void display(int array[], int n){
    for (int i = 0; i<n; i++) {
        cout << array[i]<<" ";
    }
    cout<<endl;
}
void sort(int table[], const int n) {
    for(int i = 0; i < n; i++){
        for(int j = 0; j < n-1; j++) {
            if(compare(table[j],table[j+1]))
                swap(&table[j],&table[j+1]);
        }
    }
}
int main(){
    int quantity;
    int* tab;
    ofstream outfile;
    cout<<"Enter number of element: ";
    cin>>quantity;
    tab = new int [quantity];
    cout<<"Element:\n\n"<<endl;
    for(int i=0; i < quantity; i++){
        int x = i;
        cout<<"#"<<++x<<":";
        cin>>tab[i];
    }
    sort(tab, quantity);
    cout<<"The Sorted Elements are: ";

    display(tab, quantity);
    cout<<endl;
    system ("pause");
    return 0;
}          

---

不要使用cout，而是使用文件流。

以下是完整的代码：

#include<iostream>
#include<fstream>
using namespace std;

int compare(int, int);
void sort(int[], const int);
int compare(int x, int y){
    return(x > y);
}
void swap(int *x, int *y){
    int temp;
    temp = *x;
    *x = *y;
    *y = temp;
}
void display(int array[], int n){
    for (int i = 0; i<n; i++) {
        cout << array[i] << " ";
    }
    cout << endl;
}
void writeToFile(int array[], int n){
    ofstream myfile;
    myfile.open("example.txt");
    for (int i = 0; i<n; i++) {
        myfile << array[i];
        if (i != n - 1){
            myfile << ", ";
        }
    }
    myfile.close();
}
void sort(int table[], const int n) {
    for (int i = 0; i < n; i++){
        for (int j = 0; j < n - 1; j++) {
            if (compare(table[j], table[j + 1]))
                swap(&table[j], &table[j + 1]);
        }
    }
}
int main(){
    int quantity;
    int* tab;
    ofstream outfile;
    cout << "Enter number of element: ";
    cin >> quantity;
    tab = new int[quantity];
    cout << "Element:\n\n" << endl;
    for (int i = 0; i < quantity; i++){
        int x = i;
        cout << "#" << ++x << ":";
        cin >> tab[i];
    }
    sort(tab, quantity);
    cout << "The Sorted Elements are: ";

    display(tab, quantity);
    writeToFile(tab, quantity);
    cout << endl;
    getchar();
    getchar();
    //system("pause");
    return 0;
}

---

发布所有代码是不必要的。您可以简单地询问如何将int数组保存到文件中，并显示您迄今为止所做的尝试。。。请确定流是一个流是一个流。无论是std:：cout还是某些文件流，所有文本流的工作原理都是一样的。

void writeToFile(int array[], int n){
    ofstream myfile;
    myfile.open("example.txt");
    for (int i = 0; i<n; i++) {
        myfile << array[i];
        if (i != n - 1){
            myfile << ", ";
        }
    }
    myfile.close();
}

writeToFile(tab, quantity);