类中构造函数的原型不匹配 Hi，所以我对C++非常陌生，并且尝试通过构造函数来生成一个简单的程序，它包含几个变量，然后一些函数来改变这些值。然而我得到

“User:：User（std:：string，std:：string，std:：string，std:：string，std:：string）”的原型与类“User”中的任何原型都不匹配

main.cpp

#include <iostream>
#include "User.h"
using namespace std;
int main() {

// Simulates a current existing user
User u1("PizzaLover", "ilovepizza", "pizzaLover@gmail.com", "Tony", "Stark");

// Allows user to change their current username
u1.changeUsername();

// Allows user to change their current password
u1.changePassword();

// Allows user to change their current name
u1.changeName();

// Allows user to view their general account details
u1.printUserDetails();

return 0;

#include <iostream>
#include <stdlib.h>
#include <string>
#include "User.h"
using namespace std;
User::User(string cUsername, string cPassword, string cEmail, string cFirstName, string cLastName) {

username = cUsername;
password = cPassword;
email = cEmail;
firstName = cFirstName;
lastName = cLastName;   
}

cout << endl;
cout << "- - - - - - - - - - - - -" << endl;
cout << "Username:\t" << username << endl;
cout << "Password:\t" << password << endl;
cout << "Email:\t" << email << endl;
cout << "Name:\t" << firstName << " " << lastName << endl; 
cout << "- - - - - - - - - - - - -" << endl;
}

void User::changeUsername() {

string newUserName;

cout << endl;
cout << "Your current username is: " << username << endl;
cout << "Please input your new desired username: ";
cin >> newUserName;

if(username != newUserName) {

    username = newUserName;
    cout << "Your username has been successfully changed." << endl;
    cout << "Your new username is now: " << username << endl;
}

else {
    cout << "Your name is already set to that, next time try a new name." << 
endl;
}
}

#包括
#包括“User.h”
使用名称空间std；
int main（）{
//模拟当前现有用户
用户u1（“PizzaLover”、“ilovepizza”pizzaLover@gmail.com“托尼”、“斯塔克”）；
//允许用户更改其当前用户名
u1.changeUsername（）；
//允许用户更改其当前密码
u1.changePassword（）；
//允许用户更改其当前名称
u1.changeName（）；
//允许用户查看其常规帐户详细信息
u1.printUserDetails（）；
返回0；

}

User.h

#ifndef USER_H
#define USER_H
#include <string>
class User {

private:
    std::string username;
    std::string password;
    std::string email;
    std::string firstName;
    std::string lastName;

public:
    User(string cUsername, string cPassword, string cEmail, string cFirstName, string cLastName);
    void printUserDetails(); // this allows the user to view their account details
    void changeUsername(); // this allows the user to change their username
    void changePassword(); // this allows the user to change their password
    void changeEmail(); // this allows the user to change their email
    void changeName(); // this allows the user to change their name
    };

\ifndef用户
#定义用户
#包括
类用户{
私人：
std：：字符串用户名；
std：：字符串密码；
std：：字符串电子邮件；
std:：stringfirstname；
std：：字符串lastName；
公众：
用户（字符串cUsername、字符串cPassword、字符串cEmail、字符串cFirstName、字符串cPassword NAME）；
void printUserDetails（）；//这允许用户查看其帐户详细信息
void changeUsername（）；//这允许用户更改其用户名
void changePassword（）；//这允许用户更改其密码
void changemail（）；//这允许用户更改他们的电子邮件
void changeName（）；//这允许用户更改其名称
};

User.cpp

#include <iostream>
#include "User.h"
using namespace std;
int main() {

// Simulates a current existing user
User u1("PizzaLover", "ilovepizza", "pizzaLover@gmail.com", "Tony", "Stark");

// Allows user to change their current username
u1.changeUsername();

// Allows user to change their current password
u1.changePassword();

// Allows user to change their current name
u1.changeName();

// Allows user to view their general account details
u1.printUserDetails();

return 0;

#include <iostream>
#include <stdlib.h>
#include <string>
#include "User.h"
using namespace std;
User::User(string cUsername, string cPassword, string cEmail, string cFirstName, string cLastName) {

username = cUsername;
password = cPassword;
email = cEmail;
firstName = cFirstName;
lastName = cLastName;   
}

cout << endl;
cout << "- - - - - - - - - - - - -" << endl;
cout << "Username:\t" << username << endl;
cout << "Password:\t" << password << endl;
cout << "Email:\t" << email << endl;
cout << "Name:\t" << firstName << " " << lastName << endl; 
cout << "- - - - - - - - - - - - -" << endl;
}

void User::changeUsername() {

string newUserName;

cout << endl;
cout << "Your current username is: " << username << endl;
cout << "Please input your new desired username: ";
cin >> newUserName;

if(username != newUserName) {

    username = newUserName;
    cout << "Your username has been successfully changed." << endl;
    cout << "Your new username is now: " << username << endl;
}

else {
    cout << "Your name is already set to that, next time try a new name." << 
endl;
}
}

#包括
#包括
#包括
#包括“User.h”
使用名称空间std；
User:：User（字符串cUsername、字符串cPassword、字符串cEmail、字符串cFirstName、字符串clatname）{
用户名=cUsername；
密码=cPassword；
电子邮件=电子邮件；
firstName=cFirstName；
lastName=名称；
}
不能改变：

User(string cUsername, string cPassword, string cEmail, string cFirstName, string cLastName);

User::User(string cUsername, string cPassword, string cEmail, string cFirstName, string cLastName) {

username = cUsername;
password = cPassword;
email = cEmail;
firstName = cFirstName;
lastName = cLastName;   
}

致：

不要使用构造函数体来初始化成员。使用初始化列表。你是否在User.h中包含

？@FrançoisAndrieux是的，它有#ifndef User_h，#define User_h，#include（在修复include和

字符串

vs

std:：string

）请提供一个答案，这不会解释错误操作报告，或者OP报告完整错误消息的错误片段此答案不完整。请解释问题的原因或此解决方案是如何解决的。@Jucky Dettinger感谢您解决了此错误。但是现在编译器给出了这个错误。main.cpp:（.text+0xf8）：对“User:：User（std:：string，std:：string，std:：string，std:：string，std:：string）”以及每个functions@Surge这就是为什么我们需要一个。下次请求时请这样做。现在您必须定义该函数，否则您将继续得到该错误。顺便说一句，如果人们想因为我的答案给了你正确的答案而否决我的答案，我会毫不在意。