C++ 如何停止while循环并转到其他语句？

我想制作一个程序，跟踪CD的销售数量。我想知道哪本书最畅销。CD被分为古典音乐、乡村音乐、舞蹈、流行音乐、摇滚音乐和R&B音乐

我制作了一个菜单驱动程序，可以显示音乐类型，但是 这是我的问题：我不知道用户如何才能继续输入出售的音乐类型的数量，直到他想停止为止。在他停下来之后，他如何报告每种类型的CD销量？基本上，用户将继续计算CD的销售数量，直到他想停止销售为止

#include<iostream>
using namespace std;

int main ()
{
    int counter = 1;
    int result, Alternative = 0, Classical = 0, Country = 0, Dance = 0, Pop = 0, Rock = 0, RnB = 0;
    cout << "Choose the music genre sold (Only choose the numbers): \n1. Alternative\n";
    cout << "2. Classical\n3. Country\n4. Dance\n5. Pop\n6. Rock\n7. R&B\n\t\t\t\t\t\t\t";
    while (counter <= 100)
    {
        cin>>result;
        if(result == 1)
        {
            Alternative = Alternative + 1;
        }
        else if(result == 2)
        {
            Classical = Classical + 1;
            counter++;
        }
        else if(result == 3)
        {
            Country = Country + 1;
            counter++;
        }
        else if(result == 4)
        {
            Dance = Dance + 1;
            counter++;
        }
        else if(result == 5)
        {
            Pop = Pop + 1;
            counter++;
        }
        else if (result == 6)
        {
            Rock = Rock + 1;
            counter++;
        }
        else if (result == 7)
        {
            RnB = RnB + 1;
            counter++;
        }


        cout<<"\nAlternative:"<<Alternative;
        cout<<"\tClassical:"<<Classical;
        cout<<"\tCountry: "<<Country<<"\n";
        cout<<"Dance: "<<Dance;
        cout<<"\tPop: "<<Pop;
        cout<<"\tRock: "<<Rock;
        cout<<"\tR&B: "<<RnB<<"\t\t\t";
    }
}

#包括
使用名称空间std；
int main（）
{
int计数器=1；
int-result，Alternative=0，classic=0，Country=0，Dance=0，Pop=0，Rock=0，RnB=0；
cout因此将退出选项添加到您的cout：

cout << "2. Classical\n3. Country\n4. Dance\n5. Pop\n6. Rock\n7. R&B\n8. quit

同样，在第一个if中，您应该增加选择，即在选择的情况下。最好是在仅读取一次值后增加选择，而不是在每个条件下重复

而在while循环中打印流派的cout应该是while循环的末尾，即最后一个大括号之前，即main的末尾。
允许用户告诉您他已完成输入：

//...
cout << "...7. R&B\n999.End input \t\t\t\t\t\t\t";
do { 
   //  all your statements 
} while (result!= 999);  

while（计数器编辑：
感谢@timrau和@sfjac对
中断
、
开关
和
变量+
的建议


不必在迭代次数固定（100）后停止
while
循环[1]，您可以要求用户在完成时输入特定字符或数字

考虑以下代码，例如：

// assume you have already declared and initialized all the required variables, as in your example.

// for now we will say that this is -1, so that it doesn't count as a valid option, and so it passes our while's condition.
int result = -1;

while (result)  // condition evaluates to FALSE if user enters zero.
{
    // print out the menu.
    cout << "The menu goes here... " << endl
         << "Press 0 (zero) when you are done.";

    // get the input.
    cin >> result;

    // use switch to check against constant values. Its cleaner.
    switch (result)
    {
        case 1: Alternative++;  // For incrementing variables, use the ++ operator.
                break;

        case 2: Classical++;
                break;

        // and so on, for all your choices.
        // And then,

        default: cout << "Oops! That wasn\'t a valid choice. Try again..." << endl;
    }
}

// now the user is done, and has entered 0.
cout << "\nAlternative: " << Alternative
     << "\tClassical: " << Classical
     << "\tCountry: " << Country << "\n"
     << "Dance: " << Dance
     << "\tPop: " << Pop
     << "\tRock: " << Rock
     << "\tR&B: " << RnB << "\t\t\t";

// and yes, you can fold your cout like that, so you don't have to type "cout" every time.

//假设您已经声明并初始化了所有必需的变量，如示例中所示。
//现在我们将说这是-1，因此它不算作有效选项，因此它通过了while的条件。
int结果=-1；
while（result）//如果用户输入零，则条件的计算结果为FALSE。
{
//把菜单打印出来。
cout和
switch
和
operator++
，…谢谢你的帮助！：）但是当我试着运行你的代码时，它给了我一个错误。它说“[错误]在'while'之前预期不合格的id”？尽管我仍在根据你的建议修改我自己的代码。再次感谢。你忘了把它全部放在
main（）
中吗？
   int genre[8]={};  // create ainitalised array 
    //...  as above 
    do { 
        cin>>result;
        if (result>=0 && result<8) {
           genre[result]++;
           counter++; 
           } 
        else if (result!=999)
           cout <<"Wrong value entered!\n";
      } while (result!= 999);  

while (counter <= 100 || result == -1)
{...}

bool stop = false;
while (counter <= 100 || stop)
{
  switch(result)
  {
     case 1: ...;
     case 2: ...;
     .
     .
     .
     default:
       stop = true;
  }
}

// assume you have already declared and initialized all the required variables, as in your example.

// for now we will say that this is -1, so that it doesn't count as a valid option, and so it passes our while's condition.
int result = -1;

while (result)  // condition evaluates to FALSE if user enters zero.
{
    // print out the menu.
    cout << "The menu goes here... " << endl
         << "Press 0 (zero) when you are done.";

    // get the input.
    cin >> result;

    // use switch to check against constant values. Its cleaner.
    switch (result)
    {
        case 1: Alternative++;  // For incrementing variables, use the ++ operator.
                break;

        case 2: Classical++;
                break;

        // and so on, for all your choices.
        // And then,

        default: cout << "Oops! That wasn\'t a valid choice. Try again..." << endl;
    }
}

// now the user is done, and has entered 0.
cout << "\nAlternative: " << Alternative
     << "\tClassical: " << Classical
     << "\tCountry: " << Country << "\n"
     << "Dance: " << Dance
     << "\tPop: " << Pop
     << "\tRock: " << Rock
     << "\tR&B: " << RnB << "\t\t\t";

// and yes, you can fold your cout like that, so you don't have to type "cout" every time.