C++ 返回更改程序小数c++；

我的编程课程的一个练习要求我们为出纳编写一个程序，提示到期金额和收到金额，并计算更改。它还必须计算所需的美元、25美分硬币、10美分硬币、5美分硬币和便士的数量。它在一角硬币、五分镍币和一分钱之前工作正常。这就是输出不稳定的地方。我还注意到VisualStudio将0.10读取为.10000000000000056。镍币和便士也是如此，但美元和25美分硬币却不是这样。我尝试了几种不同的方法来修复它，但没有成功。有什么建议吗

cout << "Amount Due. \n";
double due;
cout << "$";
    cin >> due;

cout << "Amount recieved. \n";
double rec;
cout << "$";
    cin >> rec;

double change = (rec - due);
cout << "Total change= $" << change << " \n";

int dollars = change / 1.00;
change = change - dollars;

int quarters = change / .25;
change = change - quarters;

int dimes = change / .10;
change = change - dimes;

int nickels = change / .05;
change = change - nickels;

int pennies = change / .01;
change = change - pennies;

cout << "Number of dollars: " << dollars << " \n";
cout << "Number of quarters: " << quarters << " \n";
cout << "Number of dimes: " << dimes << " \n";
cout << "Number of nickels: " << nickels << " \n";
cout << "Number of pennies: " << pennies << " \n";

return 0;

到期；
cout-rec；
双重变更=（收款到期日）；
库特
continue
关键字从顶部再次启动循环。
此实现可以抵抗浮点不精确。
可能的
while(change > 0){
    if(change >= 1.00){
        dollars ++;
        change -= 1;
        continue;
    }
    if(change >= 0.25){
        quarters ++;
        change -= 0.25;
        continue;
    }
    if(change >= 0.10){
        dimes ++;
        change -= 0.1;
        continue;
    }
    if(change >= 0.05){
        nickels ++;
        change -= 0.05;
        continue;
    }
    if(change >= 0.01){
        pennies ++;
        change -= 0.01;
        continue;
    }
}