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C++ boost串行化输入流错误_C++_Serialization_Boost - Fatal编程技术网

C++ boost串行化输入流错误

C++ boost串行化输入流错误,c++,serialization,boost,C++,Serialization,Boost,我正在处理一个简单的序列化类。我一直在输入流上抛出异常。我把下面的例子放在一起,用简单的术语说明我要完成的事情 我有一个简单的boost序列化示例,我遇到了一个异常: #include <boost/serialization/serialization.hpp> #include <boost/archive/text_oarchive.hpp> #include <boost/archive/text_iarchive.hpp> #include &

我正在处理一个简单的序列化类。我一直在输入流上抛出异常。我把下面的例子放在一起,用简单的术语说明我要完成的事情

我有一个简单的boost序列化示例,我遇到了一个异常:

#include <boost/serialization/serialization.hpp> 
#include <boost/archive/text_oarchive.hpp> 
#include <boost/archive/text_iarchive.hpp> 
#include <boost/serialization/export.hpp> 
#define NVP(X) X 

class base { 
public: 
friend class boost::serialization::access; 
base (){ v1 = 10;} 
int v1; 
template<class Archive> 
void serialize(Archive & ar, const unsigned int file_version) 
{ 

    ar & NVP(v1); 
} 
virtual void bla()=0; 
}; 


class derived : public base { 
public: 
friend class boost::serialization::access; 
int v2 ; 
derived() { v2 = 100;} 
template<class Archive> 
void serialize(Archive & ar, const unsigned int file_version){ 
    boost::serialization::base_object<base>(* this); 
    ar & NVP(v2); 
} 

virtual void bla(){};
};
BOOST_CLASS_EXPORT(base);
BOOST_CLASS_EXPORT_GUID(derived, "derived");

int main ( )
{
std::stringstream ss;
boost::archive::text_oarchive ar(ss);
base *b = new derived();
ar << NVP(b);
std::cout << ss.str()<<std::endl;



std::istringstream ssi;
base *b1 = new derived();
{
boost::archive::text_iarchive ar1(ssi);
ar1 >> b1;
}
//std::cout << ssi.str();
std::cout << "v1: " << b1->v1 << std::endl;

}

如果您有任何帮助,我们将不胜感激。

您正在从一条空流中阅读:

std::istringstream ssi;
// ...
boost::archive::text_iarchive ar1(ssi);
此外,您还泄漏了此对象:

base *b1 = new derived();

下面是一个固定的示例,注意:

  • 在使用流式数据之前关闭存档是非常好的做法/重要的
  • BOOST\u CLASS\u EXPORT\u GUID(派生的,“派生的”)
    除了
    BOOST\u CLASS\u EXPORT(派生的)
  • 您可以有条件地打印v2:

    if (auto* d = dynamic_cast<derived*>(b1))
        std::cout << "v2: " << d->v2 << std::endl;
    
    印刷品

    22 serialization::archive 12 0 7 derived 1 0
    0 100
    
    v1: 10, v2: 100
    

    谢谢你,先生。这是一个有点过于接近示例的情况。现在我看到我的流中没有任何东西可以反序列化。我只是意识到我没有警告
    delete
    -ing
    反序列化。所以,:)谢谢你。过一会儿我再给你来一杯。在我的实际项目中,我仍然收到输入流错误异常。我正在努力简化这个问题。
    
    #include <boost/serialization/serialization.hpp>
    #include <boost/archive/text_oarchive.hpp>
    #include <boost/archive/text_iarchive.hpp>
    #include <boost/serialization/export.hpp>
    #include <sstream>
    
    class base {
      public:
        base(int v1) : v1(v1) {}
        virtual void bla() const = 0;
    
      private:
        friend class boost::serialization::access;
    
        template <class Archive> void serialize(Archive &ar, unsigned /*int const file_version*/) {
            ar & BOOST_SERIALIZATION_NVP(v1);
        }
      protected:
        int v1;
    };
    
    class derived : public base {
      public:
        derived(int v1 = 10, int v2 = 100) : base(v1), v2(v2) {}
        virtual void bla() const {
            std::cout << "v1: " << v1 << ", v2: " << v2 << "\n";
        }
    
      private:
        friend class boost::serialization::access;
        int v2;
        template <class Archive> void serialize(Archive &ar, unsigned /*int const file_version*/) {
            boost::serialization::base_object<base>(*this);
            ar & BOOST_SERIALIZATION_NVP(v2);
        }
    };
    
    BOOST_CLASS_EXPORT(base)
    BOOST_CLASS_EXPORT(derived)
    
    int main() {
        std::stringstream ss;
        {
            boost::archive::text_oarchive ar(ss);
            base *b = new derived();
            ar << boost::serialization::make_nvp("base", b);
    
            delete b; // TODO use RAII instead
        }
    
        std::cout << ss.str() << std::endl;
        base *deserialized = nullptr;
        {
            boost::archive::text_iarchive ar1(ss);
            ar1 >> boost::serialization::make_nvp("base", deserialized);
        }
    
        deserialized->bla();
        delete deserialized;
    }
    
    22 serialization::archive 12 0 7 derived 1 0
    0 100
    
    v1: 10, v2: 100