C# 鼠标点击到达后窗WPF
我创建了一种处理对话框,显示某个进程的进程。它包含一个进程栏和一个标签。代码如下:C# 鼠标点击到达后窗WPF,c#,wpf,xaml,C#,Wpf,Xaml,我创建了一种处理对话框,显示某个进程的进程。它包含一个进程栏和一个标签。代码如下: public class ProcessingDialog { FrontWindow win; public ProcessingDialog(int min, int max, string initialMessage,string title, bool isContineous) { Thread th= new Threa
public class ProcessingDialog
{
FrontWindow win;
public ProcessingDialog(int min, int max, string initialMessage,string title, bool isContineous)
{
Thread th= new Thread(new ThreadStart(delegate()
{
win = new FrontWindow();
win.Title = title;
if (isContineous == false)
{
win.ProgressBarProgress.Minimum = min;
win.ProgressBarProgress.Maximum = max;
}
else
win.ProgressBarProgress.IsIndeterminate = true;
win.LabelStatus.Content = initialMessage;
win.ShowInTaskbar = false;
win.Topmost = true;
win.ShowDialog();
}
));
th.SetApartmentState(ApartmentState.STA);
th.Start();
}
public void Increment(int margin)
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.ProgressBarProgress.Value+=margin; }), null); ;
}
public void Reset()
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.ProgressBarProgress.Value=0; }), null); ;
}
public void ChangeMessage(string message)
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.LabelStatus.Content=message; }), null); ;
}
public void Close()
{
win.Dispatcher.Invoke(new ThreadStart(delegate { win.Close(); }), null); ;
}
}
这是FrontWindow的标记:
<Window x:Class="WpfApplicationUnleashed.FrontWindow"
xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
Title="FrontWindow" Height="165" Width="300" WindowStyle="ThreeDBorderWindow" WindowStartupLocation="CenterOwner" ResizeMode="NoResize">
<DockPanel>
<ProgressBar x:FieldModifier="public" x:Name="ProgressBarProgress" Height="15" Margin="20" DockPanel.Dock="Top" VerticalAlignment="Top"></ProgressBar>
<Label x:FieldModifier="public" x:Name="LabelStatus" Margin="10" VerticalAlignment="Top" HorizontalAlignment="Left" DockPanel.Dock="Bottom"></Label>
</DockPanel>
</Window>
问题是,当它被显示时,如果我再次单击按钮,当对话框关闭时,它会再次打开。我的意思是它不会被点击,因为它是模态的,但它只是排队,当对话框关闭时,它会被点击
如何防止这种情况发生?可能是在按钮上写一个CanExecute方法,如果命令已经在执行中,它可以防止命令被执行。如果在前窗口打开时不能使用后窗口,我会在加载前窗口时设置一个事件来禁用后窗口,然后在关闭时,启用后窗口
private void button1_Click(object sender, RoutedEventArgs e)
{
ProcessingDialog pd = new ProcessingDialog(0, 10, "Starting", "Processing", false);
Thread.Sleep(1000);
pd.ChangeMessage("Step 1");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 2");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 3");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 4");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 5");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 6");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 7");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 8");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 9");
pd.Increment(1);
Thread.Sleep(1000);
pd.ChangeMessage("Step 10");
pd.Increment(1);
Thread.Sleep(1000);
pd.Close();
}