C# windowsPhone 8:在stackpanel中向listview.Template添加json数据，而不使用modal

我想通过使用C#代码而不使用模式将json数据添加到listview项内的stackpanel（名称：expand）中。。。 我已经解析了json数据……但我不知道如何在不使用modal的情况下将其附加到stackpanel中名为“Expand”的listview项 这是我的XAML

    <ListView.Items>
                </ListView.Items>                

                <ListView.ItemTemplate>
                    <DataTemplate>
                        <Grid>

                      <Border Tapped="Border_Tap" Height="90">
                         <StackPanel  x:Name="ParentStackPanel" Width="380" Margin="0,5,0,5">



                                <StackPanel Background="Black" Margin="60,-80,0,0" Grid.Row="0" Grid.Column="1"   VerticalAlignment="Center" HorizontalAlignment="Left">
                                    <TextBlock Text="{Binding CompanyName1}" FontSize="20" FontStyle="Normal">

                                    </TextBlock>
                                </StackPanel> 

<StackPanel DataContext="expand1"  Name="expand" Background="White" Height="220">



                                </StackPanel>
                            </Border>
                        </Grid>

                    </DataTemplate>
                </ListView.ItemTemplate>
            </ListView>

感谢为您的json获取类，它非常方便：

public class Invoice
{
     public string TF { get; set; }
     public string BF { get; set; }
     public string MD { get; set; }
     public string EFM { get; set; }
     public string ATT { get; set; }
     public string FPK { get; set; }
 }

 public class Example
 {
     public Invoice Invoice { get; set; }
     public string TF { get; set; }
 }

 public class RootObject
 {
     public List<Example> Example { get; set; }
 }

---

让我知道它是否有效

您已经使用了modal…我希望不使用modaltry进行动态反序列化，或者对对象进行反序列化

public class Invoice
{
     public string TF { get; set; }
     public string BF { get; set; }
     public string MD { get; set; }
     public string EFM { get; set; }
     public string ATT { get; set; }
     public string FPK { get; set; }
 }

 public class Example
 {
     public Invoice Invoice { get; set; }
     public string TF { get; set; }
 }

 public class RootObject
 {
     public List<Example> Example { get; set; }
 }

var objects = JsonConvert.DeserializeObject<RootObject>(jsonString);

public class Invoice
{
     [Newtonsoft.Json.JsonProperty(PropertyName = "CompanyName1")]
     public string TF { get; set; }

     [Newtonsoft.Json.JsonProperty(PropertyName = "ComapnyName2")]
     public string BF { get; set; }
 }