C# 在C中反序列化时获取InvalidOperationException#
我正在使用一个基于XML的.config文件来存储一些记录。 我的XML如下:C# 在C中反序列化时获取InvalidOperationException#,c#,xml-serialization,xml-deserialization,invalidoperationexception,C#,Xml Serialization,Xml Deserialization,Invalidoperationexception,我正在使用一个基于XML的.config文件来存储一些记录。 我的XML如下: <?xml version="1.0" encoding="utf-8"?> <Data_List xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Configuration> <
<?xml version="1.0" encoding="utf-8"?>
<Data_List xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Configuration>
<Name>1st Week</Name>
<Binary>
<Field>field1</Field>
<Version>1.0</Version>
</Binary>
<Binary>
<Field>field2</Field>
<Version>2.0</Version>
</Binary>
</Configuration>
<Configuration>
<Name>2nd Week</Name>
<Binary>
<Field>field1</Field>
<Version>2.0</Version>
</Binary>
<Binary>
<Field>field2</Field>
<Version>4.0</Version>
</Binary>
</Configuration>
</Data_List>
public Binary
{
public String Field;
public String Version;
}
public Configuration
{
public String Name;
public List<Binary> Binary_List = new List<Binary>();
public GetfromXML()
{
List<Configuration> lists = new List<Configuration>();
TextReader reader = new StreamReader("Data_List.config");
XmlSerializer serializer = new XmlSerializer(typeof(List<Configuration>));
lists=(List<Configuration>)serializer.Deserialize(reader);
reader.Close();
}
第一周
字段1
1
字段2
2
第二周
字段1
2
字段2
4
我使用的C代码如下:
<?xml version="1.0" encoding="utf-8"?>
<Data_List xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Configuration>
<Name>1st Week</Name>
<Binary>
<Field>field1</Field>
<Version>1.0</Version>
</Binary>
<Binary>
<Field>field2</Field>
<Version>2.0</Version>
</Binary>
</Configuration>
<Configuration>
<Name>2nd Week</Name>
<Binary>
<Field>field1</Field>
<Version>2.0</Version>
</Binary>
<Binary>
<Field>field2</Field>
<Version>4.0</Version>
</Binary>
</Configuration>
</Data_List>
public Binary
{
public String Field;
public String Version;
}
public Configuration
{
public String Name;
public List<Binary> Binary_List = new List<Binary>();
public GetfromXML()
{
List<Configuration> lists = new List<Configuration>();
TextReader reader = new StreamReader("Data_List.config");
XmlSerializer serializer = new XmlSerializer(typeof(List<Configuration>));
lists=(List<Configuration>)serializer.Deserialize(reader);
reader.Close();
}
公共二进制文件
{
公共字符串字段;
公共字符串版本;
}
公共配置
{
公共字符串名称;
公共列表二进制_List=新列表();
公共GetfromXML()
{
列表=新列表();
TextReader=newstreamreader(“Data_List.config”);
XmlSerializer serializer=新的XmlSerializer(typeof(List));
lists=(List)序列化程序。反序列化(reader);
reader.Close();
}
我收到一个异常,说“XML文档(2,2)中有一个错误”。
有人能帮忙吗?我认为问题在于您的模型没有很好地结构化。换句话说,序列化程序不知道如何读取您的.xml 您的xml错误。当您有列表
<ArrayOfT></ArrayOfT>
public ServiceMap Deserialize()
{
ServiceMap serviceMap = new ServiceMap();
try
{
using (var fileStream = new FileStream(Settings.ServiceMapPath, FileMode.Open))
{
XmlReaderSettings settings = new XmlReaderSettings();
settings.IgnoreComments = true;
using (XmlReader reader = XmlReader.Create(fileStream, settings))
{
serviceMap = _serializer.Deserialize(reader) as ServiceMap;
}
}
}
catch (FileNotFoundException)
{
MessageBox.Show("File 'ServiceMap.xml' could not be found!");
}
return serviceMap;
}
我的ServiceMap类:
[XmlRoot("ServiceMap")]
public class ServiceMap
{
[XmlArray("Nodes")]
[XmlArrayItem("Node")]
public List<Node> Nodes = new List<Node>();
[XmlArray("Groups")]
[XmlArrayItem("Group")]
public List<Group> Groups = new List<Group>();
[XmlArray("Categories")]
[XmlArrayItem("Category")]
public List<Category> Categories = new List<Category>();
}
[XmlRoot(“ServiceMap”)]
公共类服务映射
{
[XmlArray(“节点”)]
[XmlArrayItem(“节点”)]
公共列表节点=新列表();
[XmlArray(“组”)]
[XmlArrayItem(“集团”)]
公共列表组=新列表();
[XmlArray(“类别”)]
[XmlArrayItem(“类别”)]
公共列表类别=新列表();
}
编辑:我的XML:
<?xml version="1.0" encoding="utf-8"?>
<ServiceMap xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http:// www.w3.org/2001/XMLSchema">
<Nodes>
<Node Name="Predrag">
<Children>
<Child>dijete1</Child>
<Child>dijete2</Child>
<Child>dijete3</Child>
<Child>dijete4</Child>
</Children>
<Parents>
<Parent>roditelj1</Parent>
<Parent>roditelj2</Parent>
<Parent>roditelj3</Parent>
</Parents>
<Group Name="Grupa" />
<Category Name="Kategorija" />
</Node>
<Node Name="Tami">
<Children>
<Child>dijete1</Child>
<Child>dijete2</Child>
</Children>
<Parents>
<Parent>roditelj1</Parent>
</Parents>
<Group Name="Grupa2" />
<Category Name="Kategorija2" />
</Node>
迪杰特1
dijete2
dijete3
dijete4
roditelj1
roditelj2
roditelj3
迪杰特1
dijete2
roditelj1
查看消息以及exception的InnerException属性,它应该准确地指出错误所在。此外,从外观上看,它不需要标记。它是否提供了更多信息,例如错误是什么?我建议您将序列化从图片中删除-是否可以将文档作为XML文档加载以启动with?您是如何生成XML数据的?请在发布代码时使用复制/粘贴。这不会编译。您能提供您正在使用的XML文件吗?我仍然无法获取,因为我觉得模型是结构化的。当然,在这里(在上面的帖子中):)