C# 使用Newtonsoft.JSON添加JSON属性

我有一些JSON看起来像这样：

{
    "staticInfo": {
        "browser": "Chrome",
        "browserVersion": "54.0",
        "packageNumber": "XXX",
        "user": "user"
    }
    ,
    "request": {
        "server": "E",
        "steps": {
            "Step1": {
                "start": "11/30/2016 20:11:26.494",
                "end": "11/30/2016 20:11:26.510"
            }
            ,
            "Step2": {
                "start": 1480536689237,
                "end": 1480536689357
            }
            ,
            "Step3": {
                "start": "Wed, 11/30/2016 20:12:25.229 GMT",
                "end": "Wed, 11/30/2016 20:12:25.246 GMT"
            }            
        }
        ,
        "url": "SomeURL",
        "trackingId": "99809eb5-c36b-4199-83d6-847c7b0489d1:0"
    }   
}

我正在尝试添加Step4，因此最终的JSON如下所示

{
    "staticInfo": {
        "browser": "Chrome",
        "browserVersion": "54.0",
        "packageNumber": "XXX",
        "user": "user"
    }
    ,
    "request": {
        "server": "E",
        "steps": {
            "Step1": {
                "start": "11/30/2016 20:11:26.494",
                "end": "11/30/2016 20:11:26.510"
            }
            ,
            "Step2": {
                "start": 1480536689237,
                "end": 1480536689357
            }
            ,
            "Step3": {
                "start": "Wed, 11/30/2016 20:12:25.229 GMT",
                "end": "Wed, 11/30/2016 20:12:25.246 GMT"
            }
            ,
            "Step4": {
                "start": "SomeData",
                "end": "SomeData"
            }

        }
        ,
        "url": "SomeURL",
        "trackingId": "99809eb5-c36b-4199-83d6-847c7b0489d1:0"
    }    
}

---

因此，我基本上是在尝试添加一个

步骤4

。我正试图使用

Newtonsoft.Json

来实现这一点。我知道我可以使用基本的字符串解析来完成，但为了保持一致性，我想使用

Newtonsoft.Json

类

由于

JObject

还实现了

IDictionary

，因此您可以执行以下操作：

var jObj = JObject.Parse(json);
jObj["request"]["steps"]["Step4"] = JToken.FromObject(new { start = "some", end = "somedata" });
var newjson = jObj.ToString( Newtonsoft.Json.Formatting.Indented);

或者使用

动态

关键字

dynamic jObj = JObject.Parse(json);
jObj.request.steps.Step4 = JToken.FromObject(new { start = "some", end = "somedata" });
var newjson = jObj.ToString( Newtonsoft.Json.Formatting.Indented);

---

请阅读。关键短语：“搜索、研究”和“解释……任何阻碍您自己解决问题的困难”。很好的观察，坦率地说，我不知道如何实现

IDictionary