C# 使用backgroundworker手动停止调试
我正在使用C# 使用backgroundworker手动停止调试,c#,wpf,backgroundworker,visual-studio-debugging,C#,Wpf,Backgroundworker,Visual Studio Debugging,我正在使用BackgroundWorker(带有进度条的弹出窗口)编写一个WPF C#项目 我开始调试(F5键)以检查我的程序。完成BackgroundWorker并关闭弹出窗口后,关闭Main窗口不会自动停止调试过程。我必须手动点击Shift+F5来停止调试 我认为BackgroundWorker应该自动处理线程。但无论如何,我仍然在RunWorkerCompleted方法中调用backgroundworker.Dispose()和backgroundworker.CancelAsync()。
BackgroundWorker
(带有进度条的弹出窗口)编写一个WPF C#项目
我开始调试(F5键)以检查我的程序。完成BackgroundWorker
并关闭弹出窗口后,关闭Main窗口
不会自动停止调试过程。我必须手动点击Shift+F5来停止调试
我认为BackgroundWorker
应该自动处理线程。但无论如何,我仍然在RunWorkerCompleted
方法中调用backgroundworker.Dispose()
和backgroundworker.CancelAsync()
。然而,在关闭弹出窗口并完成BackgroundWorker
时,我仍然必须手动执行Shift+F5停止调试
后台发生了什么事情,避免了程序自动停止调试?
我怎么知道
注意:我已确保backgroundworker已完成工作,并在我关闭它之前完成。使用弹出窗口和BackgroundWorker,它会在我关闭主窗口时自动停止调试
[用代码编辑]
public partial class MainWindow : Window
{
BackgroundWorker backgroundworker1 = new BackgroundWorker();
PopUp pop1 = new PopUp();
public MainWindow()
{
InitializeComponent();
backgroundworker1.DoWork += BackgroundWorker_DoWork;
backgroundworker1.RunWorkerCompleted += BackgroundWorker_RunWorkerCompleted;
backgroundworker1.WorkerReportsProgress = true;
backgroundworker1.ProgressChanged += BackgroundWorker_ProgressChanged;
backgroundworker1.WorkerSupportsCancellation = true;
}
private void startBtn_Click(object sender, RoutedEventArgs e)
{
pop1 = new PopUp();
int iteration = 0;
if (int.TryParse(iterationTb1.Text, out iteration))
{
pop1.Show();
backgroundworker1.Dispose();
backgroundworker1.RunWorkerAsync(iteration);
outputTb1.Text = "running...";
}
}
private void cancelBtn_Click(object sender, RoutedEventArgs e)
{
pop1.Close();
backgroundworker1.CancelAsync();
}
public static int DoSlowProcess(int iterations, BackgroundWorker worker, DoWorkEventArgs e)
{
int result = 0;
for (int i = 0; i <= iterations; i++)
{
if (worker != null)
{
if (worker.CancellationPending)
{
e.Cancel = true;
return result;
}
if (worker.WorkerReportsProgress)
{
int percentComplete = (int)((float)i / (float)iterations * 100);
worker.ReportProgress(percentComplete);
}
}
Thread.Sleep(100);
result = i;
}
return result;
}
private void BackgroundWorker_DoWork(object sender, DoWorkEventArgs e)
{
var bgw = sender as BackgroundWorker;
e.Result = DoSlowProcess((int)e.Argument, bgw, e);
}
private void BackgroundWorker_RunWorkerCompleted(object sender, RunWorkerCompletedEventArgs e)
{
if (e.Error != null)
{
MessageBox.Show(e.Error.Message);
}
else if (e.Cancelled)
{
outputTb1.Text = "Canceled";
}
else
{
outputTb1.Text = e.Result.ToString();
backgroundworker1.CancelAsync();
backgroundworker1.Dispose();
pop1.Close();
pop1.progressBar1.Value = 0;
}
}
private void BackgroundWorker_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
pop1.progressBar1.Value = e.ProgressPercentage;
pop1.progressLb1.Content = e.ProgressPercentage.ToString();
}
}
公共部分类主窗口:窗口
{
BackgroundWorker backgroundworker1=新的BackgroundWorker();
PopUp pop1=新的PopUp();
公共主窗口()
{
初始化组件();
backgroundworker1.DoWork+=BackgroundWorker_DoWork;
backgroundworker1.RunWorkerCompleted+=BackgroundWorker\u RunWorkerCompleted;
backgroundworker1.WorkerReportsProgress=true;
backgroundworker1.ProgressChanged+=BackgroundWorker\u ProgressChanged;
backgroundworker1.WorkerSupportsScanCellation=true;
}
私有无效开始单击(对象发送方,路由目标)
{
pop1=新弹出窗口();
int迭代=0;
if(int.TryParse(iterationTb1.Text,out iteration))
{
pop1.Show();
backgroundworker1.Dispose();
backgroundworker1.RunWorkerAsync(迭代);
OutputB1.Text=“正在运行…”;
}
}
私有作废取消点击(对象发送者,路由目标)
{
pop1.Close();
backgroundworker1.CancelAsync();
}
公共静态int-DoSlowProcess(int迭代、后台工作人员、DoWorkEventArgs e)
{
int结果=0;
对于(int i=0;iOK),我可以重现您的问题并找到原因
更改此行:
// PopUp pop1 = new PopUp(); <-- this never-used Win was blocking your close-down.
PopUp pop1 = null;
创建对象只是为了初始化一个变量,然后覆盖它总是一种反模式。在这种情况下,它实际上是有害的,因为您创建了一个窗口,但从未显示()或关闭()
请注意,Backgroundworker没有参与。它不可能参与,它使用线程池,这意味着后台线程。您可以在几个Backgroundworker没有出现问题的情况下关闭一个应用程序。某些东西让您的进程保持活动状态,而它可能不是bgw。我认为这是我的想法,但当我没有Backgroundworker时,它就不会参与op自动调试。我怎么才能知道呢?我同意Henk的观点,它可能不是后台工作程序。当调试器处于这种状态时,您可以执行“全部中断”并使用“线程”窗口查看每个线程正在执行的操作吗?我执行了“全部中断”,它只在VS2010中显示“无可用源代码”。我找不到窗口调用“线程”,有“IntelliTrace”和“Output”窗口,但它们不提供任何有用的建议。若要找到任何地方,请发布与显示弹出窗口和关闭窗口相关的所有代码。
pop1 = new PopUp();
int iteration = 0;