C# 在ASP.NET核心Web API的HttpGet方法中返回模型的单个属性

我必须在ASP.NET核心API中的GetAll方法内返回模型的单个属性。 这是我的模型：

using System;
using System.Collections.Generic;

namespace ProjectWayneAPI.Models
{
public partial class Consignment
{

    public Guid Id { get; set; }
    public DateTime? DateCreated { get; set; }
    public bool? Deleted { get; set; }
    public string CustomerReference { get; set; }
    public string ConsignmentNote { get; set; }
    public Guid AccountId { get; set; }
    public Guid BookedByUser { get; set; }
    public string DescriptionToLeave { get; set; }

    public virtual Account Account { get; set; }
    public virtual User BookedByUserNavigation { get; set; }
    public virtual User CheckedByUserNavigation { get; set; }
    public virtual User ModifiedByUserNavigation { get; set; }
    public virtual User QuotedByUserNavigation { get; set; }
}

}

我必须只返回托运单，但我必须在控制器的方法中提取所有托运单

这是我的控制器：

[Route("api/[controller]")]
[ApiController]
public class ConsignmentsController : ControllerBase
{
    private readonly WayneContext _context;

    public ConsignmentsController(WayneContext context)
    {
        _context = context;
    }

    //GET: api/Consignment Notes
    [Route("[connote]")]
    [HttpGet]
    public async Task<ActionResult<IEnumerable<Consignment>>> GetConsignmentNote()
    {
        var connote = await _context.Consignment
            .Include(x => x.ConsignmentNote)
            .ToListAsync();
        return connote;
    }
    // GET: api/Consignments
    [HttpGet]
    public async Task<ActionResult<IEnumerable<Consignment>>> GetConsignment()
    {
        var consignments = await _context.Consignment
            .Where(c => c.Deleted == false)
            .Include(bu=> bu.BookedByUserNavigation)
            .ToListAsync();
        return consignments; 
    }
}

---

我必须使用这个方法返回所有隐含的内容public async Task>>getcommitmentnote，如果您检查方法内部的linq查询，那么该查询将返回异常。在这种情况下，我如何覆盖[HttpGet]呢？

嗨，如果您尝试这样的方法会怎么样：

//[Route("[connote]")] < --remove route and call your method GET to verride httpget .. it will match the api/Consignments [GET]
    //[HttpGet]
    public async Task<ActionResult<IEnumerable<ConsignmentNote>>> Get()
    {
        var connote = await _context.Consignment
            .Include(x => x.ConsignmentNote)
            .ToListAsync();
        return connote.Select(xx=>xx.ConsignmentNote).ToList();
    }

希望它能帮助你

Include用于ie您的导航属性，如Account，而不是选择普通属性的子集，如CommissionNote

如果您只需要CommissionNote属性，则应选择新的寄售，并仅填充该特定属性：

var connote = await _context.Consignment
                            .Select(x => new Consignment 
                             { 
                                ConsignmentNote = x.ConsignmentNote
                             })
                            .ToListAsync();
return connote; // List<Consignment>

---

如果成功了，那么你应该投票并接受答案。点击复选框。我想你搞错了。我为我的回答道歉。我只是想为我的问题提供完整的答案。显然，如果没有你的回答，我可能不得不花更多的时间在谷歌上。

public async Task<ActionResult<IEnumerable<string>>> GetConsignmentNote() 
{
    var connote = await _context.Consignment
                                .Select(x =>  x.ConsignmentNote)
                                .ToListAsync();
    return connote; // List<string>
}