C# 如何将C对象列表导出到excel电子表格?

C# 如何将C对象列表导出到excel电子表格?,c#,.net,excel,C#,.net,Excel,我有一个从Excel电子表格创建的C列表,我想将其导出到Excel。我怎样才能完成这项任务?这只是一个控制台项目。我不打算在.Net应用程序中显示数据。我只需要数据表 var fileName = string.Format("C:\\Users\\SGurmu\\Desktop\\Data 091510.xls"); var connectionString = string.Format("Provider=Microsoft.Jet.OLEDB.4.0; data source={0};

我有一个从Excel电子表格创建的C列表,我想将其导出到Excel。我怎样才能完成这项任务?这只是一个控制台项目。我不打算在.Net应用程序中显示数据。我只需要数据表

var fileName = string.Format("C:\\Users\\SGurmu\\Desktop\\Data 091510.xls");
var connectionString = string.Format("Provider=Microsoft.Jet.OLEDB.4.0; data source={0}; Extended Properties=Excel 8.0;", fileName);

var fileName2 = string.Format("C:\\Users\\SGurmu\\Desktop\\Copy of Prototype.xls");
var connectionString2 = string.Format("Provider=Microsoft.Jet.OLEDB.4.0; data source={0}; Extended Properties=Excel 8.0;", fileName);

var adapter = new OleDbDataAdapter("SELECT * FROM [Sheet1$]", connectionString);
var ds = new DataSet();

adapter.Fill(ds, "contacts");

var data = ds.Tables["contacts"].AsEnumerable();

List<EmployeeData> query = data.Where(x => x.Field<string>("First_Name") != string.Empty).Select(x =>

new EmployeeData
    {
    empID = x.Field<double>("EMPLOYEE"),
    firstName = x.Field<string>("First_Name"),
    lastName = x.Field<string>("Last_Name"),
    JobCategory = x.Field<string>("Job Title"),
    StartDate = x.Field<Nullable<DateTime>>("Hire Dt"),
    EndDate =   x.Field<Nullable<DateTime>>("Term Dt"),
    TermReason = x.Field<string>("Term Reason"),
    PeggedUID = x.Field<Nullable<double>>("Pegged UserID"),
    UpdateDate = x.Field<Nullable<DateTime>>("Last Updated")
    }).ToList();

也许您可以尝试使用Infodinamica.Framework.Expotable包,该包托管在Nuget中

有了它,你可以做这样的事情

List<EmployeeData> query = data.Where(x => x.Field<string>("First_Name") != string.Empty).Select(x =>

    new EmployeeData
        {
        empID = x.Field<double>("EMPLOYEE"),
        firstName = x.Field<string>("First_Name"),
        lastName = x.Field<string>("Last_Name"),
        JobCategory = x.Field<string>("Job Title"),
        StartDate = x.Field<Nullable<DateTime>>("Hire Dt"),
        EndDate =   x.Field<Nullable<DateTime>>("Term Dt"),
        TermReason = x.Field<string>("Term Reason"),
        PeggedUID = x.Field<Nullable<double>>("Pegged UserID"),
        UpdateDate = x.Field<Nullable<DateTime>>("Last Updated")
        }).ToList();

    IExportEngine engine = new ExcelExportEngine();
    engine.AddData(EmployeeData);
    MemoryStream memory = engine.Export();
唯一的问题是,文档是西班牙语的

项目页面是

西班牙语的导出示例为

它还支持以西班牙语导入文件

右键单击项目并管理nuget软件包。 添加ClosedXML nuget包 使用ClosedXML.Excel添加;到类文件的顶部。 将“ToExcelFile”方法添加到类中。 将列表转换为数据表。 托氏法

public static bool ToExcelFile(this DataTable dt, string filename)
{
    bool Success = false;
    //try
    //{
        XLWorkbook wb = new XLWorkbook();

        wb.Worksheets.Add(dt, "Sheet 1");

        if (filename.Contains("."))
        {
            int IndexOfLastFullStop = filename.LastIndexOf('.');

            filename = filename.Substring(0, IndexOfLastFullStop) + ".xlsx";

        }

        filename = filename + ".xlsx";

        wb.SaveAs(filename);

        Success = true;

    //}
    //catch (Exception ex)
    //{
        //ex.HandleException();

    //}
    return Success;
}
将列表转换为数据表

    public static DataTable ToDataTable(List<string> list)
    {
        DataTable MethodResult = null;

        DataTable dt = new DataTable();
        dt.Columns.Add("Item", );

        foreach(string s in list)
        {
            DataRow dr = dt.NewRow();
            dr[0] = s;
            dt.Rows.Add(dr);

        }

        dt.AcceptChanges();

        MethodResult = dt;

        return MethodResult;

    }

你不能导出到一个简单的csv文件或xml文件,然后导入到一个预计算的excel文件中吗?你尝试过这种方法吗?转到标题为的部分,这里是为列表移植的方法。列表
    public static DataTable ToDataTable(List<string> list)
    {
        DataTable MethodResult = null;

        DataTable dt = new DataTable();
        dt.Columns.Add("Item", );

        foreach(string s in list)
        {
            DataRow dr = dt.NewRow();
            dr[0] = s;
            dt.Rows.Add(dr);

        }

        dt.AcceptChanges();

        MethodResult = dt;

        return MethodResult;

    }