C# sql查询以列出不带groupby/aggregate的列

我的两张桌子看起来像这样

工作台

buyer   timeArrived               billed     paid

ABC     2013-02-08 10:30:00       60$        45$
CTS     2013-02-18 10:30:00       100$       80$
ABC     2012-03-11 10:30:00       60$        40$
MNT     2012-02-08 10:30:00       100$       60$
CTS     2012-03-11 10:30:00       60$        40$

买方表格

buyer

ABC
MNT
CTS
GH

为了在买家“最后一次露面”时搜索他，我从买家表查询到商店表 像

知道ABC和CTS什么时候购物很好 但是如何获得“账单”和“付费”列呢

SELECT
 b.buyer,
 s.*
FROM buyer_t AS b
INNER JOIN shop as s ON b.buyer = s.buyer
INNER JOIN
(
   SELECT buyer, MAX(timeArrived) AS LastSeen
   FROM shop
   GROUP BY buyer
) AS s2  ON s.buyer = s2.buyer
        AND s.timeArrived = s2.lastSeen
WHERE s.buyer IN ('ABC', 'CTS');

这将为您提供：

| BUYER |                     TIMEARRIVED | BILLED | PAID |
-----------------------------------------------------------
|   ABC | February, 08 2013 10:30:00+0000 |    60$ |  45$ |
|   CTS | February, 18 2013 10:30:00+0000 |   100$ |  80$ |

---

或：由于您使用的是SQL Server 2005，因此您可以使用（

ROW_NUMBER（））OVER（partitionby…ORDER BY…）来执行以下操作：

WITH CTE
AS
(
    SELECT
      s.*,
      ROW_NUMBER() OVER(PARTITION BY s.buyer
                        ORDER BY timeArrived DESC) AS Rownumber
    FROM buyer_t AS b
    INNER JOIN shop as s ON b.buyer = s.buyer
    WHERE s.buyer IN ('ABC', 'CTS')
) 
SELECT Buyer, TimeArrived, Billed, Paid
FROM CTE 
WHERE Rownumber = 1;

请尝试以下方法：

SELECT
 b.buyer,
 s.*
FROM buyer_t AS b
INNER JOIN shop as s ON b.buyer = s.buyer
INNER JOIN
(
   SELECT buyer, MAX(timeArrived) AS LastSeen
   FROM shop
   GROUP BY buyer
) AS s2  ON s.buyer = s2.buyer
        AND s.timeArrived = s2.lastSeen
WHERE s.buyer IN ('ABC', 'CTS');

这将为您提供：

| BUYER |                     TIMEARRIVED | BILLED | PAID |
-----------------------------------------------------------
|   ABC | February, 08 2013 10:30:00+0000 |    60$ |  45$ |
|   CTS | February, 18 2013 10:30:00+0000 |   100$ |  80$ |


或：由于您使用的是SQL Server 2005，因此您可以使用（
ROW_NUMBER（））OVER（partitionby…ORDER BY…）来执行以下操作：

WITH CTE
AS
(
    SELECT
      s.*,
      ROW_NUMBER() OVER(PARTITION BY s.buyer
                        ORDER BY timeArrived DESC) AS Rownumber
    FROM buyer_t AS b
    INNER JOIN shop as s ON b.buyer = s.buyer
    WHERE s.buyer IN ('ABC', 'CTS')
) 
SELECT Buyer, TimeArrived, Billed, Paid
FROM CTE 
WHERE Rownumber = 1;

@user1944477查询中没有
v
别名，请尝试
s.buyer
或
b.buyer
。@user1944477是的，它为您设置了最近的日期，最大日期是最近的日期。@user1944477没问题，这是正确的。如果有什么问题，请随时再次询问。如果你觉得有帮助，试着去做。当然，但我不能接受答案。它不接受，显示4，但返回到3..：（@user1944477没问题，这是Stackoverflow中的工作方式：）@user1944477在您的查询中没有
v
别名，请尝试
s.buyer
或
b.buyer
。@user1944477是的，它将您划分为最近的日期，最大日期是最近的日期。@user1944477没问题，这是正确的。如果有什么问题，请随时再次询问。如果你觉得有帮助，试着去做。当然，但我不能接受答案。它不接受，显示4，但返回到3..：（@user1944477没关系，这是Stackoverflow中的工作原理：）