C# 将XML字符串反序列化为复杂类型
我的Xml(我无法更改): 反序列化此XML的工作与预期的一样,但我想将C# 将XML字符串反序列化为复杂类型,c#,xml,deserialization,C#,Xml,Deserialization,我的Xml(我无法更改): 反序列化此XML的工作与预期的一样,但我想将Country属性更改为复杂类型,如下所示: public Country Country { get; set; } 然后在country.name属性中输入国家名称“JAPAN”,有什么想法吗?您可以用如下属性装饰country类的name属性: [XmlRoot("result")] public class VehicleDetails { public string Type { get; set; }
Country
属性更改为复杂类型,如下所示:
public Country Country { get; set; }
然后在
country.name
属性中输入国家名称“JAPAN”,有什么想法吗?您可以用如下属性装饰country
类的name
属性:
[XmlRoot("result")]
public class VehicleDetails
{
public string Type { get; set; }
public string Make { get; set; }
public Country Country { get; set; }
}
public class Country
{
[XmlText]
public string Name { get; set; }
}
还要注意,我已经去掉了[Serializable]
属性。它对于XML序列化是无用的。此属性用于二进制/远程序列化
下面是一个完整的示例,将按预期打印JAPAN
:
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
[XmlRoot("result")]
public class VehicleDetails
{
public string Type { get; set; }
public string Make { get; set; }
public Country Country { get; set; }
}
public class Country
{
[XmlText]
public string Name { get; set; }
}
class Program
{
static void Main()
{
var serializer = new XmlSerializer(typeof(VehicleDetails));
var xml =
@"<result>
<Type>MAZDA</Type>
<Make>RX-8</Make>
<Country>JAPAN</Country>
</result>";
using (var reader = new StringReader(xml))
using (var xmlReader = XmlReader.Create(reader))
{
var result = (VehicleDetails)serializer.Deserialize(xmlReader);
Console.WriteLine(result.Country.Name);
}
}
}
使用系统;
使用System.IO;
使用System.Xml;
使用System.Xml.Serialization;
[XmlRoot(“结果”)]
公营车辆详情
{
公共字符串类型{get;set;}
公共字符串Make{get;set;}
公共国家{get;set;}
}
公营国家
{
[XmlText]
公共字符串名称{get;set;}
}
班级计划
{
静态void Main()
{
var serializer=新的XmlSerializer(typeof(VehicleDetails));
变量xml=
@"
马自达
RX-8
日本
";
使用(var reader=newstringreader(xml))
使用(var xmlReader=xmlReader.Create(reader))
{
var result=(VehicleDetails)序列化程序。反序列化(xmlReader);
Console.WriteLine(result.Country.Name);
}
}
}
这是VB 2010的等价物
Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization
Public Module Module1
Public Sub Main()
Dim serializer = New XmlSerializer(GetType(VehicleDetails))
Dim xml = "<result> <Type>MAZDA</Type> <Make>RX-8</Make> <Country>JAPAN</Country> </result>"
Using reader = New StringReader(xml)
Using xmlReader__1 = XmlReader.Create(reader)
Dim result = DirectCast(serializer.Deserialize(xmlReader__1), VehicleDetails)
Console.WriteLine(result.Country.Name)
End Using
End Using
End Sub
<XmlRoot("result")> _
Public Class VehicleDetails
Public Property Type() As String
Get
Return m_Type
End Get
Set(value As String)
m_Type = value
End Set
End Property
Private m_Type As String
Public Property Make() As String
Get
Return m_Make
End Get
Set(value As String)
m_Make = value
End Set
End Property
Private m_Make As String
Public Property Country() As Country
Get
Return m_Country
End Get
Set(value As Country)
m_Country = value
End Set
End Property
Private m_Country As Country
End Class
Public Class Country
<XmlText()> _
Public Property Name() As String
Get
Return m_Name
End Get
Set(value As String)
m_Name = value
End Set
End Property
Private m_Name As String
End Class
End Module
Imports System.IO
导入System.Xml
导入System.Xml.Xml
公共模块模块1
公用分干管()
Dim serializer=新的XmlSerializer(GetType(VehicleDetails))
Dim xml=“马自达RX-8日本”
使用阅读器=新的StringReader(xml)
使用xmlReader__1=xmlReader.Create(reader)
Dim结果=DirectCast(序列化程序.反序列化(xmlReader__1),车辆详细信息)
Console.WriteLine(result.Country.Name)
终端使用
终端使用
端接头
_
公营车辆详情
作为字符串的公共属性类型()
得到
返回m_类型
结束
设置(值为字符串)
m_类型=值
端集
端属性
私有m_类型为字符串
公共属性Make()作为字符串
得到
退货
结束
设置(值为字符串)
m_Make=价值
端集
端属性
私人m_Make As String
公共财产国()作为国家
得到
返回m_国家
结束
设置(值为国家/地区)
m_国家=价值
端集
端属性
作为国家的私人m_国家
末级
公营国家
_
作为字符串的公共属性名()
得到
返回m_名称
结束
设置(值为字符串)
m_Name=值
端集
端属性
私有m_名称作为字符串
末级
端模块
谢谢Darin,效果很好。我可以将两个XML节点聚合为一个复杂类型吗?e、 g.0error
,将这两个属性合并为一个public Error Error{get;set;}
属性,其中类型Error
有两个属性,code
和message
?问题是,我希望能够动态地完成这项工作,而不是将所有事情都硬编码。希望能够调用一个以XML对象作为参数的函数,并让它返回一个对象,或者让XML对象本身像我们所拥有的那样是可寻址的。如果无法从运行时发现的字符串中创建属性,则无法使用此函数..:(
using System;
using System.IO;
using System.Xml;
using System.Xml.Serialization;
[XmlRoot("result")]
public class VehicleDetails
{
public string Type { get; set; }
public string Make { get; set; }
public Country Country { get; set; }
}
public class Country
{
[XmlText]
public string Name { get; set; }
}
class Program
{
static void Main()
{
var serializer = new XmlSerializer(typeof(VehicleDetails));
var xml =
@"<result>
<Type>MAZDA</Type>
<Make>RX-8</Make>
<Country>JAPAN</Country>
</result>";
using (var reader = new StringReader(xml))
using (var xmlReader = XmlReader.Create(reader))
{
var result = (VehicleDetails)serializer.Deserialize(xmlReader);
Console.WriteLine(result.Country.Name);
}
}
}
Imports System.IO
Imports System.Xml
Imports System.Xml.Serialization
Public Module Module1
Public Sub Main()
Dim serializer = New XmlSerializer(GetType(VehicleDetails))
Dim xml = "<result> <Type>MAZDA</Type> <Make>RX-8</Make> <Country>JAPAN</Country> </result>"
Using reader = New StringReader(xml)
Using xmlReader__1 = XmlReader.Create(reader)
Dim result = DirectCast(serializer.Deserialize(xmlReader__1), VehicleDetails)
Console.WriteLine(result.Country.Name)
End Using
End Using
End Sub
<XmlRoot("result")> _
Public Class VehicleDetails
Public Property Type() As String
Get
Return m_Type
End Get
Set(value As String)
m_Type = value
End Set
End Property
Private m_Type As String
Public Property Make() As String
Get
Return m_Make
End Get
Set(value As String)
m_Make = value
End Set
End Property
Private m_Make As String
Public Property Country() As Country
Get
Return m_Country
End Get
Set(value As Country)
m_Country = value
End Set
End Property
Private m_Country As Country
End Class
Public Class Country
<XmlText()> _
Public Property Name() As String
Get
Return m_Name
End Get
Set(value As String)
m_Name = value
End Set
End Property
Private m_Name As String
End Class
End Module