C# 在C中使用TCP从客户端错误接收多个响应#

因此，我试图制作一个代码，其中TCP将接受所有涉及重复接受客户端的客户端，但当我使用该代码时，我无法收到客户端的任何响应，因此如何解决此问题

消息框甚至不会在服务器上弹出

缓冲区位置的代码（后台工作程序）：

当客户端将响应发送回服务器（后台工作程序）时，我将显示messagebox的代码：

下面是代码的一部分，其中客户端从服务器接收响应，然后向服务器发送消息（代码的一部分，但主要关注这一点）：

---

不能从非UI线程（在本例中为后台工作线程）更新UI

更改：

while(true)
        {
            string data = Encoding.Unicode.GetString(buffer, 0, 
streamer.Read(buffer, 0, client.ReceiveBufferSize));
            if(data == "Response_Command_329873123709123")
            {
                MessageBox.Show(Encoding.Unicode.GetString(buffer, 0, 
streamer.Read(buffer, 0, client.ReceiveBufferSize)), "Client Response");
            }
        }

…致：

private void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e)
    {
        BackgroundWorker worker = sender as BackgroundWorker;

    while(true)
    {
        string data = Encoding.Unicode.GetString(buffer, 0, 
                       streamer.Read(buffer, 0, client.ReceiveBufferSize));
        if(data == "Response_Command_329873123709123")
        {
            var message = Encoding.Unicode.GetString(buffer, 0, 
                                   streamer.Read(buffer, 0, client.ReceiveBufferSize));

            worker.ReportProgress (0,  message);
        }
    }

    private void backgroundWorker1_ProgressChanged(object sender, ProgressChangedEventArgs e)
    {
        MessageBox.Show((string)e.UserState, "Client Response");
    }

---

我想我的缓冲区部分出错了，但我已经修复了

int databases = streamer.Read(buffers, 0, buffers.Length);
                string data = Encoding.Unicode.GetString(buffers, 0, databases);
                if (data == "Response_Command_329873123709123")
                {
                    byte[] datacen = new byte[client.ReceiveBufferSize];
                    int main = streamer.Read(datacen, 0, datacen.Length);
                    var message = Encoding.Unicode.GetString(datacen, 0, main);
                    MessageBox.Show(message, "Client Response");
                }

---

谢谢你的帮助，但是由于某些原因，这不起作用。我已经用你提供给我的新代码编辑了我的问题。那么代码中有错误吗？虽然我也启用了reportprocess@zhiyan114当然，你需要将上述模式应用到你的其他员工身上。对不起，我应该说清楚的。看看你是如何快速更新你的答案的，我已经把它修好了，是的，messagebox在后台工作程序中使用时确实会显示出来。@zhiyan114将你的声明作为一个答案发布给大家看

while(true)
        {
            string data = Encoding.Unicode.GetString(buffer, 0, 
streamer.Read(buffer, 0, client.ReceiveBufferSize));
            if(data == "Response_Command_329873123709123")
            {
                MessageBox.Show(Encoding.Unicode.GetString(buffer, 0, 
streamer.Read(buffer, 0, client.ReceiveBufferSize)), "Client Response");
            }
        }

private void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e)
    {
        BackgroundWorker worker = sender as BackgroundWorker;

    while(true)
    {
        string data = Encoding.Unicode.GetString(buffer, 0, 
                       streamer.Read(buffer, 0, client.ReceiveBufferSize));
        if(data == "Response_Command_329873123709123")
        {
            var message = Encoding.Unicode.GetString(buffer, 0, 
                                   streamer.Read(buffer, 0, client.ReceiveBufferSize));

            worker.ReportProgress (0,  message);
        }
    }

    private void backgroundWorker1_ProgressChanged(object sender, ProgressChangedEventArgs e)
    {
        MessageBox.Show((string)e.UserState, "Client Response");
    }

int databases = streamer.Read(buffers, 0, buffers.Length);
                string data = Encoding.Unicode.GetString(buffers, 0, databases);
                if (data == "Response_Command_329873123709123")
                {
                    byte[] datacen = new byte[client.ReceiveBufferSize];
                    int main = streamer.Read(datacen, 0, datacen.Length);
                    var message = Encoding.Unicode.GetString(datacen, 0, main);
                    MessageBox.Show(message, "Client Response");
                }