C# 保存文件-xmlSerializer
我正在使用以下代码创建一个序列化文件的方法:C# 保存文件-xmlSerializer,c#,xml,serialization,xml-serialization,streamwriter,C#,Xml,Serialization,Xml Serialization,Streamwriter,我正在使用以下代码创建一个序列化文件的方法: public void Save(Object file, Type type, String path) { // Create a new Serializer XmlSerializer serializer = new XmlSerializer(typeof(type)); // Create a new StreamWriter StreamWriter writer = new StreamWriter
public void Save(Object file, Type type, String path)
{
// Create a new Serializer
XmlSerializer serializer = new XmlSerializer(typeof(type));
// Create a new StreamWriter
StreamWriter writer = new StreamWriter(@path);
// Serialize the file
serializer.Serialize(writer, file);
// Close the writer
writer.Close();
}
但Visual Studio在我尝试构建时告诉我:
“错误1找不到类型或命名空间名称“type”(是否缺少using指令或程序集引用?)
"
为什么会这样
**编辑*
有效的新代码:
public void Save(Object file, String path, Type type)
{
// Create a new Serializer
XmlSerializer serializer = new XmlSerializer(type);
// Create a new StreamWriter
TextWriter writer = new StreamWriter(path);
// Serialize the file
serializer.Serialize(writer, file);
// Close the writer
writer.Close();
}
public object Read(String path, Type type)
{
// Create a new serializer
XmlSerializer serializer = new XmlSerializer(type);
// Create a StreamReader
TextReader reader = new StreamReader(path);
// Deserialize the file
Object file;
file = (Object)serializer.Deserialize(reader);
// Close the reader
reader.Close();
// Return the object
return file;
}
通过调用读取:
myClass newClass = (myClass)Read(file, type);
Save(object, path, type);
通过调用保存:
myClass newClass = (myClass)Read(file, type);
Save(object, path, type);
谢谢!
埃里克
而不是
XmlSerializer serializer = new XmlSerializer(typeof(type));
XmlSerializer
采用类型
参数<代码>类型已经是类型类型,因此不需要对其调用typeof()
typeof()
仅当您将类名或泛型参数放在括号内时才需要。您的错误出现在新的XmlSerializer(typeof(type))代码>。您不需要typeof
<代码>新的XmlSerializer(类型)代码>就足够了
由于序列化了文件
对象(其类型可以在函数中确定),因此不必传递其类型。因此,您的代码可以重新编写为
public void Save<T>(T file, String path)
{
XmlSerializer serializer = new XmlSerializer(typeof(T));
using (StreamWriter writer = new StreamWriter(path))
{
serializer.Serialize(writer, file);
}
}
public void保存(T文件,字符串路径)
{
XmlSerializer serializer=新的XmlSerializer(typeof(T));
使用(StreamWriter=新StreamWriter(路径))
{
serializer.Serialize(编写器、文件);
}
}
新的XmlSerializer(类型)代码>+无需在@path