C# 如何按日期时间对字典进行分组并对int进行求和
我有以下代码:C# 如何按日期时间对字典进行分组并对int进行求和,c#,linq,lambda,group-by,aggregate-functions,C#,Linq,Lambda,Group By,Aggregate Functions,我有以下代码: var tradeReqsBySegment = segGroups.Join(pPeriods, s => s.MarketSegmentId, p => p.EntityId, (s, p) => new { SegmentCode = s.SegmentCode, // string Time = p.StartLocal, // datetime TradeRequirement = p.V
var tradeReqsBySegment = segGroups.Join(pPeriods, s => s.MarketSegmentId, p => p.EntityId, (s, p) => new
{
SegmentCode = s.SegmentCode, // string
Time = p.StartLocal, // datetime
TradeRequirement = p.Volume // double
})
.GroupBy(s => s.SegmentCode)
.ToDictionary(g => g.Key, g => g.ToDictionary(i => i.Time, i=>i.TradeRequirement));
我希望将g.ToDictionary(I=>I.Time,I=>I.TradeRequirement))
按时间分组,并将TradeRequirement
相加或平均。我该如何处理这个问题
此外,是否可以按月对时间进行分组,如get:
Time - TradeReq
01/2013 - 500
02/2013 - 234
...
您可以使用匿名类型同时获取:
Sum
和Average
:
var tradeReqsBySegment = segGroups.Join(pPeriods, s => s.MarketSegmentId, p => p.EntityId, (s, p) => new
{
SegmentCode = s.SegmentCode, // string
Time = p.StartLocal, // datetime
TradeRequirement = p.Volume // double
})
.GroupBy(s => s.SegmentCode)
.ToDictionary(g => g.Key,
g => g.GroupBy(gr => new DateTime(gr.Time.Year, gr.Time.Month, 1))
.ToDictionary(gr => gr.Key.ToString("MM/yyyy"),
gr => new {
Sum = gr.Sum(s => s.TradeRequirement),
Avg = gr.Average(s => s.TradeRequirement)
}));
请参阅按月份分组。确实非常有用。:)
var tradeReqsBySegment = segGroups.Join(pPeriods, s => s.MarketSegmentId, p => p.EntityId, (s, p) => new
{
SegmentCode = s.SegmentCode, // string
Time = p.StartLocal, // datetime
TradeRequirement = p.Volume // double
})
.GroupBy(s => s.SegmentCode)
.ToDictionary(g => g.Key,
g => g.GroupBy(gr => new DateTime(gr.Time.Year, gr.Time.Month, 1))
.ToDictionary(gr => gr.Key.ToString("MM/yyyy"),
gr => new {
Sum = gr.Sum(s => s.TradeRequirement),
Avg = gr.Average(s => s.TradeRequirement)
}));