C# SendGrid没有发送电子邮件?
我已经围绕sendgrid编写了一个Wrapper服务,除了实际发送电子邮件之外,所有的工作都可以完成 服务:C# SendGrid没有发送电子邮件?,c#,sendgrid,C#,Sendgrid,我已经围绕sendgrid编写了一个Wrapper服务,除了实际发送电子邮件之外,所有的工作都可以完成 服务: public class SendGridService : ISendGridService { public async Task Send(Email email) { var preparedEmail = PrepareEmail(email); var apiKey = Configur
public class SendGridService : ISendGridService
{
public async Task Send(Email email)
{
var preparedEmail = PrepareEmail(email);
var apiKey = ConfigurationManager.AppSettings["sendGridApiKey"];
var transportWeb = new Web(apiKey);
await transportWeb.DeliverAsync(preparedEmail);
}
//other methods that prepare the email
}
我正在使用的测试类,以查看电子邮件是否已发送:
[Test]
public void Send_ShouldSendEmailToOneAddress()
{
//arrange
//uses NBuilder to mock the object
var email = Builder<Email>.CreateNew()
.With(x => x.Recipient = "me@me.com")
.With(x => x.Sender = "me@me.com")
.With(x => x.SenderName = "me")
.With(x => x.FilePathAttachement = null)
.With(x => x.Html = null)
.Build();
//act
var temp = _sut.Send(email);
//assert
}
[测试]
public void Send_ShouldSendEmailToOneAddress()
{
//安排
//使用NBuilder模拟对象
var email=Builder.CreateNew()
.With(x=>x.Recipient=”me@me.com")
.With(x=>x.Sender=”me@me.com")
.With(x=>x.SenderName=“me”)
.With(x=>x.FilePathAttachement=null)
.With(x=>x.Html=null)
.Build();
//表演
var temp=_sut.Send(电子邮件);
//断言
}
我意识到测试并不是真正的测试任何东西,但我希望在收件箱中看到电子邮件,然后围绕代码编写真假测试
问题是我从未收到过电子邮件。我缺少什么使电子邮件真正发送。您没有正确调用异步方法。在单元测试的上下文中,它应该是:
[Test]
public async Task Send_ShouldSendEmailToOneAddress()
{
//arrange
//uses NBuilder to mock the object
var email = Builder<Email>.CreateNew()
.With(x => x.Recipient = "me@me.com")
.With(x => x.Sender = "me@me.com")
.With(x => x.SenderName = "me")
.With(x => x.FilePathAttachement = null)
.With(x => x.Html = null)
.Build();
//act
await _sut.Send(email);
//assert
}
[测试]
公共异步任务发送\u ShouldSendEmailToOneAddress()
{
//安排
//使用NBuilder模拟对象
var email=Builder.CreateNew()
.With(x=>x.Recipient=”me@me.com")
.With(x=>x.Sender=”me@me.com")
.With(x=>x.SenderName=“me”)
.With(x=>x.FilePathAttachement=null)
.With(x=>x.Html=null)
.Build();
//表演
等待发送(电子邮件);
//断言
}
即:
1) 将测试更改为返回async Task
而不是void
2) wait
您的异步方法
当您在程序中正确使用邮件发送者时,您需要确保您的
async/await
的使用是如果您登录到sendgrid,sendgrid是否正在接收/处理任何内容?您的DeliverAsync
方法是什么样的?@cal5barton否,就sendgrid而言,没有任何内容happening@X3074861XThat这不是我的方法。它随SendGrid api一起提供。您是否从SendGrid获得成功的api调用?这给了我一个编译器错误:无法将void赋值给隐式类型变量,而我正在将测试中的系统赋值给temp。@Robert。。只需删除temp
(您的SendGridService
不会返回任何内容)