C# 二维显示中带正方形的随机数
有人能告诉我为什么我的第二列不是拳头的正方形吗?以下是我所拥有的:C# 二维显示中带正方形的随机数,c#,random,perfect-square,C#,Random,Perfect Square,有人能告诉我为什么我的第二列不是拳头的正方形吗?以下是我所拥有的: const int NUM_ROWS = 10; const int NUM_COLS = 2; int[,] randint = new int [NUM_ROWS,NUM_COLS]; Random randNum = new Random(); for (int row = 0; row < randint.GetLength(0); row++) { randint[row,0] = randNum.N
const int NUM_ROWS = 10;
const int NUM_COLS = 2;
int[,] randint = new int [NUM_ROWS,NUM_COLS];
Random randNum = new Random();
for (int row = 0; row < randint.GetLength(0); row++)
{
randint[row,0] = randNum.Next(1,100);
randint[row,1] = randint[row,0]*randint[row,0];
Console.Write(string.Format("{0,5:d} {0,5:d}\n", randint[row,0], randint[row,1]));
const int NUM_ROWS=10;
常数int NUM_COLS=2;
int[,]randint=新int[NUM_ROWS,NUM_COLS];
Random randNum=新的Random();
for(int row=0;row
是的。您只是将第一个数字打印到控制台。您的字符串格式应该是“{0,5:d}{1,5:d}\n”