C# 二进制搜索算法:数组中每个记录的文本文件

C# 二进制搜索算法:数组中每个记录的文本文件,c#,arrays,algorithm,text,binary,C#,Arrays,Algorithm,Text,Binary,我有一个包含90000个整数的数组,还有一个txt文件, 我必须按顺序读取txt文件,并且不允许将其放入数组中,即文本文件中的每条记录 我必须使用二进制搜索在数组中找到相应的数字。然后显示匹配的数字数量 我就是这样做的,但它只找到第一个匹配的号码,然后停止 static void Main(string[] args) { //etc(OTHER CODE)....................... Array.Sort(NumFile); // BINARY SEA

我有一个包含90000个整数的数组,还有一个txt文件, 我必须按顺序读取txt文件,并且不允许将其放入数组中,即文本文件中的每条记录 我必须使用二进制搜索在数组中找到相应的数字。然后显示匹配的数字数量

我就是这样做的,但它只找到第一个匹配的号码,然后停止

static void Main(string[] args)
{
    //etc(OTHER CODE).......................
    Array.Sort(NumFile);
    // BINARY SEARCHHHH
    int last,
    first,
    mid = 0,
    target,
    found = 0,
    counter = 0;
    string run;

    //Stats
    int Finds = 0;
    first = 0;
    last = NumFile.Length - 1;            
    //READ TextFile
    StreamReader search = new StreamReader("Records.txt");
    target = int.Parse(search.ReadLine());
    //while (last >= first && found == 0)
    while (last >= first && found == 0 && (run = search.ReadLine()) != null)
    {
        mid = (last + first) / 2;
        if (target == NumFile[mid])
        {
            found = 1;
        }
        else
        {
            if (target < NumFile[mid])
            {
                 last = mid - 1;
            }
            else
            {
                 first = mid + 1;
            }

        }
        if (found == 1)
        {
            Console.WriteLine("\nThe number was found at location {0}", mid);
            Finds++;
        }
        else
        {
             //Console.WriteLine("\nNumber not found");                  
        }

    }

    Console.WriteLine("Binary Search Statistics \t Hits:{0} ,hits);        

}    .

这是while循环,请查看while条件find==0

while (last >= first && found == 0 && (run = search.ReadLine()) != null)
{
    mid = (last + first) / 2;
    if (target == NumFile[mid])
    {
        found = 1;
    }
    else
    {
        if (target < NumFile[mid])
        {
             last = mid - 1;
        }
        else
        {
             first = mid + 1;
        }

    }
    if (found == 1)
    {
        Console.WriteLine("\nThe number was found at location {0}", mid);
        Finds++;
    }
    else
    {
         //Console.WriteLine("\nNumber not found");                  
    }

}

我不明白你为什么一直在二进制搜索循环中读取文件。它可能在查找第一个数字时跳过了整个文件。我想你需要两个嵌套的循环:外部的文件读取循环和内部的搜索循环。这是学校作业吗?你为什么不打个电话呢?
if (found == 1)
{
    Console.WriteLine("\nThe number was found at location {0}", mid);
    Finds++;
    found =0;
}