C# 将文件从ASP.NET核心web api发布到另一个ASP.NET核心web api
我们正在构建一个web应用程序,它由Angular2前端、ASP.NET核心web api公共后端和ASP.NET核心web api专用后端组成 将文件从Angular2上传到公共后端works。但是我们更愿意将它们转发到私有后端 现行工作守则C# 将文件从ASP.NET核心web api发布到另一个ASP.NET核心web api,c#,asp.net,asp.net-core,C#,Asp.net,Asp.net Core,我们正在构建一个web应用程序,它由Angular2前端、ASP.NET核心web api公共后端和ASP.NET核心web api专用后端组成 将文件从Angular2上传到公共后端works。但是我们更愿意将它们转发到私有后端 现行工作守则 [HttpPost] public StatusCodeResult Post(IFormFile file) { ... } 从那里,我可以使用file.CopyTo(fileStream)将文件保存到磁盘 但是,我希望将该文件或那些文件,或者理
[HttpPost]
public StatusCodeResult Post(IFormFile file)
{
...
}
从那里,我可以使用file.CopyTo(fileStream)将文件保存到磁盘
但是,我希望将该文件或那些文件,或者理想情况下,将整个请求重新发送到我的第二个web api核心
我不知道如何使用asp.net core的HttpClient类实现这一点
我试过各种各样的东西,比如
StreamContent ss = new StreamContent(HttpContext.Request.Body);
var result = client.PostAsync("api/Values", ss).Result;
但是我的第二个后端得到一个空文件
我有一种感觉,可以将文件作为流发送,并在另一端重建它们,但无法使其工作
解决方案必须使用两个web api core。调用私有后端api时忽略HttpClient,是否可以从公共core api项目引用私有core api项目,并直接从core api项目调用控制器?请参阅请求仍然为null/空。如果请求带有一个值,那么问题在于HttpClient的使用 理想情况下,您希望为要分发给消费客户端的私有核心API创建一个包库(类似于SDK)。这就像一个包装器/代理。通过这种方式,您可以隔离专用后端系统,并对其进行隔离故障排除。因此,您可以将公共核心API项目(即专用后端客户端)作为nuget包引用。Solution DMZ中的公共后端
[HttpPost]
public StatusCodeResult Post(IFormFile file)
{
try
{
if (file != null && file.Length > 0)
{
using (var client = new HttpClient())
{
try
{
client.BaseAddress = new Uri(currentPrivateBackendAddress);
byte[] data;
using (var br = new BinaryReader(file.OpenReadStream()))
data = br.ReadBytes((int)file.OpenReadStream().Length);
ByteArrayContent bytes = new ByteArrayContent(data);
MultipartFormDataContent multiContent = new MultipartFormDataContent();
multiContent.Add(bytes, "file", file.FileName);
var result = client.PostAsync("api/Values", multiContent).Result;
return StatusCode((int)result.StatusCode); //201 Created the request has been fulfilled, resulting in the creation of a new resource.
}
catch (Exception)
{
return StatusCode(500); // 500 is generic server error
}
}
}
return StatusCode(400); // 400 is bad request
}
catch (Exception)
{
return StatusCode(500); // 500 is generic server error
}
}
专用后端
[HttpPost]
public void Post()
{
//Stream bodyStream = HttpContext.Request.Body;
if (Request.HasFormContentType)
{
var form = Request.Form;
foreach (var formFile in form.Files)
{
var targetDirectory = Path.Combine(_appEnvironment.WebRootPath, "uploads");
var fileName = GetFileName(formFile);
var savePath = Path.Combine(targetDirectory, fileName);
using (var fileStream = new FileStream(savePath, FileMode.Create))
{
formFile.CopyTo(fileStream);
}
}
}
}
嗨,我也有同样的问题,这就是我的工作原理: 我的设置是netCore MVC netCoreApi 我的MVC控制器看起来像:
[HttpPost("UploadFiles")]
public async Task<IActionResult> Post(List<IFormFile> files)
{
Sp4RestClient dataPovider = new Sp4RestClient("http://localhost:60077/");
long size = files.Sum(f => f.Length);
foreach (var file in files)
{
await dataPovider.ImportFile(file);
}
return Ok();
}
要查看完整代码,请参见我的RestClient Post方法:
public async Task<RestResult<T>> Post<T>(HttpContent content)
{
using (HttpClient httpClient = new HttpClient())
{
HttpResponseMessage response = await httpClient.PostAsync(Endpoint, content);
if (response.StatusCode == HttpStatusCode.Created)
{
T result = JsonConvert.DeserializeObject<T>(await response.Content.ReadAsStringAsync());
return new RestResult<T> { Result = result, ResultCode = HttpStatusCode.OK };
}
RestResult<T> nonOkResult =
new RestResult<T> { Result = default(T), ResultCode = response.StatusCode, Message = await response.Content.ReadAsStringAsync() };
return nonOkResult;
}
}
公共异步任务发布(HttpContent)
{
使用(HttpClient HttpClient=new HttpClient())
{
HttpResponseMessage响应=等待httpClient.PostAsync(端点,内容);
if(response.StatusCode==HttpStatusCode.Created)
{
T result=JsonConvert.DeserializeObject(wait response.Content.ReadAsStringAsync());
返回新的RestResult{Result=Result,ResultCode=HttpStatusCode.OK};
}
RestResult非OK结果=
新RestResult{Result=default(T),ResultCode=response.StatusCode,Message=wait response.Content.ReadAsStringAsync()};
返回非OK结果;
}
}
//是的,我知道我没有得到HttpStatusCode.Created back;)
快乐编码;) API代码
[Route("api/upload/{id}")]
[HttpPost]
public async Task<IActionResult> Post(string id)
{
var filePath = @"D:\" + id; //+ Guid.NewGuid() + ".png";
if (Request.HasFormContentType)
{
var form = Request.Form;
foreach (var formFile in form.Files)
{
if (formFile.Length > 0)
{
using (var stream = new FileStream(filePath, FileMode.Create))
{
await formFile.CopyToAsync(stream);
}
}
}
}
return Ok(new { Path = filePath });
}
我也遇到过类似的情况——我需要一种代理方法,不仅可以转发文件,还可以转发JSON数据等等。我不想对我的代理中的数据进行任何分析,让最终的接收者来处理它 因此,在我的帮助下,我得出了以下工作解决方案:
byte[] arr = null;
using (var mems = new MemoryStream())
{
// read entire body into memory first because it might be chunked with unknown length
await request.Body.CopyToAsync(mems);
await mems.FlushAsync(); // not sure if needed after CopyToAsync - better safe then sorry
arr = mems.ToArray();
}
msg.Content = new ByteArrayContent(arr);
msg.Content.Headers.ContentLength = arr.Length;
// keep content-type header "as is" to preserve multipart boundaries etc.
msg.Content.Headers.TryAddWithoutValidation("Content-Type", request.ContentType);
var response = await _httpClient.SendAsync(msg);
我用复杂的请求测试了它,该请求包含多部分表单数据和JSON字段以及多个附加文件,所有的数据都毫无问题地到达了我的后端服务器。这个解决方案不是很好,因为你在公共后端的内存中加载了整个内容-想象一下,如果你的文件超过了RAM的容量……这是唯一适合我的解决方案@乔治·尼西莫夫:你知道另一种选择吗?似乎对我的网关文件传递很有效。感谢您提供的解决方案。无需转换为ByteArrayContent,您可以添加类似以下内容的StreamContent对象:multiContent.add(新的StreamContent(file.OpenReadStream(),“file”,file.FileName));你好我还想发送一个参数与此特别是为用户我上传这个文件。我需要随此请求发送userId。你也能帮忙吗?还有一件事。我如何使用postman来点击这个特定的上传api?它的身体是什么?
[Route("api/upload/{id}")]
[HttpPost]
public async Task<IActionResult> Post(string id)
{
var filePath = @"D:\" + id; //+ Guid.NewGuid() + ".png";
if (Request.HasFormContentType)
{
var form = Request.Form;
foreach (var formFile in form.Files)
{
if (formFile.Length > 0)
{
using (var stream = new FileStream(filePath, FileMode.Create))
{
await formFile.CopyToAsync(stream);
}
}
}
}
return Ok(new { Path = filePath });
}
[Route("home/UploadFile")]
[HttpPost]
public IActionResult UploadFile(IFormFile file)
{
if (file == null || file.Length == 0)
return Content("file not selected");
var client = new HttpClient();
byte[] data;
using (var br = new BinaryReader(file.OpenReadStream()))
data = br.ReadBytes((int)file.OpenReadStream().Length);
ByteArrayContent bytes = new ByteArrayContent(data);
MultipartFormDataContent multiContent = new MultipartFormDataContent
{
{ bytes, "file", file.FileName }
};
var result = client.PostAsync("http://localhost:2821/api/upload/" + file.FileName, multiContent).Result;
return RedirectToAction("file");
}
byte[] arr = null;
using (var mems = new MemoryStream())
{
// read entire body into memory first because it might be chunked with unknown length
await request.Body.CopyToAsync(mems);
await mems.FlushAsync(); // not sure if needed after CopyToAsync - better safe then sorry
arr = mems.ToArray();
}
msg.Content = new ByteArrayContent(arr);
msg.Content.Headers.ContentLength = arr.Length;
// keep content-type header "as is" to preserve multipart boundaries etc.
msg.Content.Headers.TryAddWithoutValidation("Content-Type", request.ContentType);
var response = await _httpClient.SendAsync(msg);