C# 在XPath中使用变量

这是可行的，但我想使用文本组1作为变量

代码试用：

[FindsBy(How = How.XPath, Using = "(.//*[normalize-space(text()) and normalize-space(.)= 'Group 1'])[1]/ancestor::app-organization//*[normalize-space(text()) and normalize-space(.)='Create a new board...']/following::input[1]")]
public IWebElement BoardNameInputField { get; set; }

我试过了，但没有成功：

string boardName = "Group 1";

[FindsBy(How = How.XPath, Using = "(.//*[normalize-space(text()) and normalize-space(.)='${boardName}'])[1]/ancestor::app-organization//*[normalize-space(text()) and normalize-space(.)='Create a new board...']")]
public IWebElement CreateNewBoard { get; set; }

可以这样做吗？

您可以将String.Format用于：

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希望这对你有帮助

将变量boardName设置为组1时，需要更改：

How.XPath, Using = "(.//*[normalize-space(text()) and normalize-space(.)='${boardName}'])[1]/ancestor::app-organization//*[normalize-space(text()) and normalize-space(.)='Create a new board...']")]

作为：

实际上，我们改变了：

normalize-space(.)='${boardName}'

致：

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在字符串插值中，$应该在字符串之前，而不是变量之前

[FindsBy(How = How.XPath, Using = $"(.//*[normalize-space(text()) and normalize-space(.)='{boardName}'])[1]/ancestor::app-organization//*[normalize-space(text()) and normalize-space(.)='Create a new board...']")]

此外，boardName需要是静态的，才能在方法范围之外使用

static string boardName = "Group 1";

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使用String.Format还是String concatenation更好这就是OP问题的答案！但是：字符串插值在编译时被转换为string.Format，因此我的答案是…：@MosheSlavin是真的，但看起来OP试图这么做，他使用了“${boardName}”。可能是重复的

normalize-space(.)='" + boardName + "'

[FindsBy(How = How.XPath, Using = $"(.//*[normalize-space(text()) and normalize-space(.)='{boardName}'])[1]/ancestor::app-organization//*[normalize-space(text()) and normalize-space(.)='Create a new board...']")]

static string boardName = "Group 1";