C# 从IEnumerable foreach循环获取值

我需要从一个JSON文件创建一个c对象，并且需要以下工作解决方案：

var deserialized = JsonConvert.DeserializeObject<JObject>(json);
var locations = (
    from state in deserialized.Properties().Select(v => v.Value).OfType<JObject>()
    from city in state.Properties().Select(v => v.Value).OfType<JArray>()
    from location in city
    select new Location
    {
        Name = location.Value<string>("Name"),
        Address = location.Value<string>("Address"),
        City = location.Value<string>("City"),
        State = location.Value<string>("State"),
        Zip = location.Value<string>("Zip")
    }).ToList();

JSON:

代码：

我试图通过使用IEnumerable来解决这个限制，但我不确定如何获取所需的值的语法

string json = File.ReadAllText(@"C:json.txt");

var deserialisedJson = (IEnumerable)JsonConvert.DeserializeObject(json);

var locations = new List<Location>();

foreach (var root in deserialisedJson)
{
    foreach (var state in (IEnumerable)root)
    {
        foreach (var city in (IEnumerable)state)
        {
            foreach (var location in (IEnumerable)city)
            {
                Location loc = new Location();

                loc.Name = //What goes here???
                loc.Address = //What goes here???
                loc.City = //What goes here???
                loc.State = //What goes here???
                loc.Zip = //What goes here???

                locations.Add(loc);
            }
        }
    }
}

此选项用于选择所需的所有位置对象：

var deserialisedJson = (IEnumerable)JsonConvert.DeserializeObject(json);
JObject jObj = JObject.Parse(json);

//Get all tokens that are under AK/(some descendant)/all items from collection
var result = jObj.SelectTokens("AK.*.[*]")
                    .Select(x => new Location
                    {
                        Name = x["Name"].Value<string>(),
                        Address = x["Address"].Value<string>(),
                        City = x["City"].Value<string>(),
                        State = x["State"].Value<string>(),
                        Zip = x["Zip"].Value<string>(),
                    }).ToList();

---

在.Net 3.5项目中进行了测试，并使用了适用于.Net的Newtonsoft.Json包。以下是一个快速解决方案：

var deserialized = JsonConvert.DeserializeObject<JObject>(json);
var locations = (
    from state in deserialized.Properties().Select(v => v.Value).OfType<JObject>()
    from city in state.Properties().Select(v => v.Value).OfType<JArray>()
    from location in city
    select new Location
    {
        Name = location.Value<string>("Name"),
        Address = location.Value<string>("Address"),
        City = location.Value<string>("City"),
        State = location.Value<string>("State"),
        Zip = location.Value<string>("Zip")
    }).ToList();

---

您可以使用CLASE让newtonsoft解决您需要的问题

public class Location
{
    public string Name { get; set; }
    public string Address { get; set; }
    public string City { get; set; }
    public string State { get; set; }
    public string Zip { get; set; }
}
public class AK
{
    public Location[] Anchorage { get; set; }
    public Location[] Fairbanks { get; set; }
}   


var ak = JsonConvert.DeserializeObject<AK>(json);

---

location[Name]？添加一个小的json示例Using location[Name]给出一个错误：无法使用[]将索引应用于“object”类型的表达式，而不是动态反序列化json=JsonConvert.DeserializeObjectjson；ClassThatHasJsonStructure反序列化Json=Json.Decodejson是否在.Net3.5中工作？您实际上不需要类型。您可以动态地反序列化它。但是我们需要json的结构。@pixelpul-这对你有帮助吗？如果你在同一个列表中需要它们，只需将它们浓缩就行了。var位置=ak.Anchorage.Concatak.Fairbanks；

var deserialized = JsonConvert.DeserializeObject<JObject>(json);
var locations = (
    from state in deserialized.Properties().Select(v => v.Value).OfType<JObject>()
    from city in state.Properties().Select(v => v.Value).OfType<JArray>()
    from location in city
    select new Location
    {
        Name = location.Value<string>("Name"),
        Address = location.Value<string>("Address"),
        City = location.Value<string>("City"),
        State = location.Value<string>("State"),
        Zip = location.Value<string>("Zip")
    }).ToList();

public class Location
{
    public string Name { get; set; }
    public string Address { get; set; }
    public string City { get; set; }
    public string State { get; set; }
    public string Zip { get; set; }
}
public class AK
{
    public Location[] Anchorage { get; set; }
    public Location[] Fairbanks { get; set; }
}   


var ak = JsonConvert.DeserializeObject<AK>(json);