Date SQLSRV不工作

我试图通过SQLSRV函数填充SQL查询中的下拉列表，它是日期格式的，但它不起作用。请帮忙

<?php

$serverName1 = "kk12334";
$connectionInfo1 = array( "Database"=>"Fruits");
$conn1 = sqlsrv_connect( $serverName1, $connectionInfo1);
$sql1="SELECT [ArrivalDate] as ADate, [ArrivalCompany] as ACompany from Fruits";
$stmt1 = sqlsrv_query( $conn1, $sql1 );

while ($data=sqlsrv_fetch_array($stmt1, SQLSRV_FETCH_ASSOC))

{ 

$checkdate= $data[ADate];
$checkacct=$data[ACompany];

$checkdateDisplay = $checkdate . "-" . $checkacct;
$checkdateDisplay = substr($checkdate, 5, 2) . "-" . substr($checkdate, 8, 2) . "-" .  substr($checkdate, 0, 4) . "_:_" . $checkacct;
echo "<option value='$checkdateDisplay'>$checkdateDisplay</option>\n";

}

?>

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您的连接数组没有遵循正确的语法，并且遗漏了重要信息：

$connectionInfo = array( "Database"=>$myDB, "PWD"=>$myPass, "UID"=>$myUser);

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此错误会阻止代码连接到数据库。您必须同时提供用户名UID和密码PWD。

请删除以下代码。这是重复的$checkdateDisplay=$checkdate.-$支票账户；但它仍然不起作用。请帮助。请注意，仅当我包含SQL Server中的日期格式列时，才会导致此问题。日期是否有单独的语法？