&引用；解析器必须是字符串或字符流，而不是datetime“；lambda aws函数中出错-can'；我想不出怎么修理它

在尝试保存/测试这个Lambda Boto3函数时，我遇到了一个非常恼人的错误。关于这个问题，这里还有其他的线程，但是我花了大约2个小时来调试它，无法找出我做错了什么（这可能是显而易见的）。任何帮助都将不胜感激

{
  "errorMessage": "Parser must be a string or character stream, not datetime",
  "errorType": "TypeError",
  "stackTrace": [
    "  File \"/var/task/lambda_function.py\", line 35, in lambda_handler\n    a = dateutil.parser.parse(instance.launch_time)\n",
    "  File \"/var/runtime/dateutil/parser/_parser.py\", line 1358, in parse\n    return DEFAULTPARSER.parse(timestr, **kwargs)\n",
    "  File \"/var/runtime/dateutil/parser/_parser.py\", line 646, in parse\n    res, skipped_tokens = self._parse(timestr, **kwargs)\n",
    "  File \"/var/runtime/dateutil/parser/_parser.py\", line 722, in _parse\n    l = _timelex.split(timestr)         # Splits the timestr into tokens\n",
    "  File \"/var/runtime/dateutil/parser/_parser.py\", line 207, in split\n    return list(cls(s))\n",
    "  File \"/var/runtime/dateutil/parser/_parser.py\", line 76, in __init__\n    '{itype}'.format(itype=instream.__class__.__name__))\n"
  ]
}

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启动时间

属性已经是datetime属性。您不需要解析它

参考：

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Instance.launch\u时间？可能已经是datetime？没错，instance.launcy\u time已经是datetime格式<代码>打印（类型（实例.启动时间））

import json
import boto3
import time
import datetime 
import dateutil
from dateutil.parser import parse


def lambda_handler(event, context):
    detailDict = event["detail"]
    ec2 = boto3.resource('ec2')
    instanceId = str(detailDict["instance-id"])
    instance = ec2.Instance(instanceId)
    instanceState = instance.state

    a = dateutil.parser.parse(instance.launch_time)
    b = current_time = datetime.datetime.now(launch_time.tzinfo)

    # returns a timedelta object 
    c = a-b  
    print('Difference: ', c) 

    minutes = c.seconds / 60
    print('Difference in minutes: ', minutes)

    Message=str(instanceId)+" is "+str(instanceState["Name"])
    return {
        'statusCode': 200,
        'body': Message
    }