Django models 没有外键例外Django
我们有一个外键为用户的模型:Django models 没有外键例外Django,django-models,django-admin,django-admin-filters,Django Models,Django Admin,Django Admin Filters,我们有一个外键为用户的模型: class Medic(models.Model): user = models.ForeignKey(User) first_name = models.CharField(max_length=100, blank=True) middle_name = models.CharField(max_length=100, blank=True) last_name = models.CharField(max_length=100,
class Medic(models.Model):
user = models.ForeignKey(User)
first_name = models.CharField(max_length=100, blank=True)
middle_name = models.CharField(max_length=100, blank=True)
last_name = models.CharField(max_length=100, blank=True)
在admin.py中,我们尝试将已注册的用户筛选为仅属于名为“staff”的组的用户,这些用户显示在Medic页面上:
from django.contrib import admin
from django.contrib.auth.models import User
from profiles.models import Medic
class StaffMed(admin.StackedInline):
model = User
def queryset(self, request):
qs = super(StaffMed, self).queryset(request).filter(group__name='staff')
return qs
class MedicAdmin(admin.ModelAdmin):
inlines = [StaffMed]
#model = Medic
admin.site.register(Medic, MedicAdmin)
然后我们得到一个例外:
class 'django.contrib.auth.models.User' has no foreignKey to class 'staff.models.Medic'
必须指定外键所在的模型:
class StaffMed(admin.StackedInline):
model = MedicAdmin
然后你需要像这样过滤:
def queryset(self, request):
qs = super(StaffMed, self).queryset(request).filter(user.group__name='staff')
return qs