Django 保存前更改表单字段值

我有一张表格：

class ReferencesForm(forms.ModelForm):

    error_css_class = 'error'   #set some css when an error
    contactName = forms.CharField(label='Contact Name:')
    company = forms.CharField(label='Company:')
    address = forms.CharField(label='Address:')
    telephoneNumber = forms.CharField(label='Telephone Number:')

    class Meta:
        fields = '__all__'
        model = References

    def __init__(self, *arg, **kwarg):
        super(ReferencesForm, self).__init__(*arg, **kwarg)
        self.empty_permitted = True
    def clean(self):
        """ Custom validation for fields
        """
        cleaned_data = super(ReferencesForm, self).clean()

        return self.cleaned_data  

并在“我的视图”文件中建立它，如下所示：

ReferencesInlineFormSet = inlineformset_factory(
        Applicant, References, form=ReferencesForm, extra=1, can_delete=False)
...
if request.method == 'POST':
    references_formset = ReferencesInlineFormSet(
        request.POST, instance=applicant)

    if (references_formset.is_valid()):
        references_formset.instance['address'] = "test";
        references_formset.save();

我不认为申请者模型在这里很重要，但如果有必要，我可以在以后添加它

我想将一些地址字段（addr1、addr2、town等）合并到一个名为“address”的数据库字段中，并考虑在视图文件中这样做

我在这里尝试了一个简单的带有“test”的作业，但收到了错误：

'Applicant' object does not support item assignment
references_formset.instance['address'] = "test"; 

---

您可以通过模型的实例访问表单的字段。例如，代替这一行：

references_formset.instance['address'] = "test";

applicant.address = "test"

试试这句话：

references_formset.instance['address'] = "test";

applicant.address = "test"

---

您可以使用以下内容：

if form.is_valid():
    obj = form.save(commit=False)
    obj.address = "test"
    obj.save()

简单：

但是要小心，这不会检查

是否有效（）。如果要执行此操作，可以使用新值实例化表单：

# NOT TESTED, NOT SURE IF THIS WORKS...
form = MyForm(instance=instance)
if form.is_valid():
    form.save()