Django 如何使用字段集而不导致registry()错误?

Django 如何使用字段集而不导致registry()错误?,django,python-3.x,django-admin,Django,Python 3.x,Django Admin,刚到django。我试图修改我的模型,在同一行上得到两个字段。在阅读了关于 我在admin.py中尝试了以下操作: from django.contrib import admin from .models import * # Register your models here. class NewsAdd(admin.ModelAdmin): fieldsets = [ (None, { 'fields': ('field1'('fiel

刚到django。我试图修改我的模型,在同一行上得到两个字段。在阅读了关于 我在admin.py中尝试了以下操作:

from django.contrib import admin
from .models import *


# Register your models here.

class NewsAdd(admin.ModelAdmin):
    fieldsets = [
        (None, {
            'fields': ('field1'('field2','field3'),'field4','field5','field6','field7')})]

class NewsDisplay(admin.ModelAdmin): 
    list_display = ('nick','hosty','msg','info','specjalista','od','do') 
    search_fields = ('nick','hosty','msg','info','specjalista','od','do') 

admin.site.register(News, NewsDisplay, NewsAdd)
请不要介意在admin.site.register中显示新闻和新闻,因为它们工作正常

将NewsAdd添加到admin.site.register后,我立即收到以下错误:

Unhandled exception in thread started by <function check_errors.<locals>.wrapper at 0x00000000044C5E18>
Traceback (most recent call last):
  File "C:\Python36\lib\site-packages\django\utils\autoreload.py", line 225, in wrapper
    fn(*args, **kwargs)
  File "C:\Python36\lib\site-packages\django\core\management\commands\runserver.py", line 109, in inner_run
    autoreload.raise_last_exception()
  File "C:\Python36\lib\site-packages\django\utils\autoreload.py", line 248, in raise_last_exception
    raise _exception[1]
  File "C:\Python36\lib\site-packages\django\core\management\__init__.py", line 337, in execute
    autoreload.check_errors(django.setup)()
  File "C:\Python36\lib\site-packages\django\utils\autoreload.py", line 225, in wrapper
    fn(*args, **kwargs)
  File "C:\Python36\lib\site-packages\django\__init__.py", line 24, in setup
    apps.populate(settings.INSTALLED_APPS)
  File "C:\Python36\lib\site-packages\django\apps\registry.py", line 120, in populate
    app_config.ready()
  File "C:\Python36\lib\site-packages\django\contrib\admin\apps.py", line 24, in ready
    self.module.autodiscover()
  File "C:\Python36\lib\site-packages\django\contrib\admin\__init__.py", line 26, in autodiscover
    autodiscover_modules('admin', register_to=site)
  File "C:\Python36\lib\site-packages\django\utils\module_loading.py", line 47, in autodiscover_modules
    import_module('%s.%s' % (app_config.name, module_to_search))
  File "C:\Python36\lib\importlib\__init__.py", line 126, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 994, in _gcd_import
  File "<frozen importlib._bootstrap>", line 971, in _find_and_load
  File "<frozen importlib._bootstrap>", line 955, in _find_and_load_unlocked
  File "<frozen importlib._bootstrap>", line 665, in _load_unlocked
  File "<frozen importlib._bootstrap_external>", line 678, in exec_module
  File "<frozen importlib._bootstrap>", line 219, in _call_with_frames_removed
  File "C:\Users\ji34ix\PycharmProjects\Diego\src\Hosting\Wmit_news\admin.py", line 21, in <module>
    admin.site.register(News, NewsDisplay, NewsAdd)
TypeError: register() takes from 2 to 3 positional arguments but 4 were given

我确信我在这里遗漏了一些非常简单的东西,但我自己无法解决它。有人能帮忙吗?

这应该是一个ModelAdmin类

register有两个参数:Model类和适当的ModelAdmin类。您试图传递三个非法参数

,并且可以组合在单个类定义中

class NewsAdmin(admin.ModelAdmin):
    fieldsets = [
        (None, {
            'fields': ('field1'('field2','field3'),'field4','field5','field6','field7')})]
    list_display = ('nick','hosty','msg','info','specjalista','od','do') 
    search_fields = ('nick','hosty','msg','info','specjalista','od','do') 

admin.site.register(News, NewsAdmin)

什么是NewsDisplay?它修改模型,以便显示所创建项目的所有属性。它位于models.py中。代码无法格式化是注释中的代码:class NewsDisplayadmin.ModelAdmin:list_display='nick','hosty','msg','info','specjalista','od','do'search_字段='nick','hosty','msg','info','specjalista','od','do'谢谢,我今天会尝试一下,让你知道。Ivan Starostin成功了。非常感谢你,你让我开心。我已把你的答案标记为我问题的解决办法。