尝试将请求图像从Django传递到Python脚本

我正在创建一个项目，其中我正在向Django本地服务器发送一个带有映像的请求。接收并保存图像，效果良好

但是，在收到图像后，我试图将该文件传递给我的python脚本。在那里，它应该运行带有图像的脚本，并将数据返回给用户

我被卡住了，因为我似乎无法将图像文件名传递给python脚本，因此无法使用图像运行脚本

有人知道如何做到这一点吗

许多（#）：是我尝试做的

视图.py

class ImageViewSet(mixins.ListModelMixin,
               mixins.CreateModelMixin,
               generics.GenericAPIView):
"""
    Upload image (Save and Run Script)
   """

parser_classes = (JSONParser, MultiPartParser, FormParser,)
queryset = UploadImageTest.objects.all()
serializer_class = ImageSerializer

def output(self, request):

    imagename = request.FILES['image']
    #imagename = request.data['image']
    #imagename = models.ImageField
    #imagename = request.FILES['image'].name
    #imagename = UploadImageTest.image
    print(imagename)

    #self.request.FILES['image']
    #inp = request.data['image']
    inp = request.FILES.get(imagename)
    out = run([sys.executable,'//Users/macbookpro//TestAPI//venv//TestImageScript.py',inp],shell=False,stdout=PIPE)
    print(out)

    return {"status": "Success", "output": str(out)}

class ImageSerializer(serializers.ModelSerializer):

class Meta:
    model = UploadImageTest
    fields = ('id', 'name', 'description', 'image')

class UploadImageTest(models.Model):
permission_classes = (IsAuthenticated,)

name = models.CharField(max_length=200)
description = models.TextField(blank=True)
image = models.ImageField(upload_to="images/", null=True, blank=True)

def __str__(self):
    return "{}".format(self.name)

序列化程序.py

class ImageViewSet(mixins.ListModelMixin,
               mixins.CreateModelMixin,
               generics.GenericAPIView):
"""
    Upload image (Save and Run Script)
   """

parser_classes = (JSONParser, MultiPartParser, FormParser,)
queryset = UploadImageTest.objects.all()
serializer_class = ImageSerializer

def output(self, request):

    imagename = request.FILES['image']
    #imagename = request.data['image']
    #imagename = models.ImageField
    #imagename = request.FILES['image'].name
    #imagename = UploadImageTest.image
    print(imagename)

    #self.request.FILES['image']
    #inp = request.data['image']
    inp = request.FILES.get(imagename)
    out = run([sys.executable,'//Users/macbookpro//TestAPI//venv//TestImageScript.py',inp],shell=False,stdout=PIPE)
    print(out)

    return {"status": "Success", "output": str(out)}

class ImageSerializer(serializers.ModelSerializer):

class Meta:
    model = UploadImageTest
    fields = ('id', 'name', 'description', 'image')

class UploadImageTest(models.Model):
permission_classes = (IsAuthenticated,)

name = models.CharField(max_length=200)
description = models.TextField(blank=True)
image = models.ImageField(upload_to="images/", null=True, blank=True)

def __str__(self):
    return "{}".format(self.name)

型号.py

class ImageViewSet(mixins.ListModelMixin,
               mixins.CreateModelMixin,
               generics.GenericAPIView):
"""
    Upload image (Save and Run Script)
   """

parser_classes = (JSONParser, MultiPartParser, FormParser,)
queryset = UploadImageTest.objects.all()
serializer_class = ImageSerializer

def output(self, request):

    imagename = request.FILES['image']
    #imagename = request.data['image']
    #imagename = models.ImageField
    #imagename = request.FILES['image'].name
    #imagename = UploadImageTest.image
    print(imagename)

    #self.request.FILES['image']
    #inp = request.data['image']
    inp = request.FILES.get(imagename)
    out = run([sys.executable,'//Users/macbookpro//TestAPI//venv//TestImageScript.py',inp],shell=False,stdout=PIPE)
    print(out)

    return {"status": "Success", "output": str(out)}

class ImageSerializer(serializers.ModelSerializer):

class Meta:
    model = UploadImageTest
    fields = ('id', 'name', 'description', 'image')

class UploadImageTest(models.Model):
permission_classes = (IsAuthenticated,)

name = models.CharField(max_length=200)
description = models.TextField(blank=True)
image = models.ImageField(upload_to="images/", null=True, blank=True)

def __str__(self):
    return "{}".format(self.name)

Python脚本

file_name = sys.argv[1]
print(file_name)


img = cv2.imread("file_name")

您是否尝试过：

request.FILES.get['image'].filename

根据ImageField的文档，它继承了包含属性

filename

（不要忘记在文档中查看此字段的描述）的所有属性

编辑

您可以改为尝试

name

attribute：

f = request.FILES['image_url']
print(dir(f))   # This shows everything we can do by using this variable
print("filename : ", f.name)

编辑：

要获得修改后的上传文件名，可以先保存对象，然后检索文件名。您可以尝试以下方法： （假设有一个名为

SomeModel

的模型，并且有一个属性

image\u url

，即ImageField）

someModel=someModel.objects.get（id=id）
数据={'image\u url'：image\u url}
序列化的_model=SomeModelSerializer（someModel，data=data，partial=True）
如果未序列化，\u model.\u是否有效（）
raise ParseError（序列化的_model.errors）
序列化的_model.save（）
打印（序列化的_model.data.get（'image _url'））#感谢您的回复。但是，它不起作用。也许我还缺少一些东西。谢谢你的支持。request.FILES.get（'image'）。name打印并获取文件名，但它总是获取“random.png”。Django会自动重命名文件，每次都创建一个唯一的文件名。我无法获取新生成的文件名。它总是抓取“random.png”。