基于组的Django服务内容

我有一个调查应用程序，它包括以下模型类：调查、回答、问题和答案。我想做的是根据用户所属的组限制问题

我已经通读了Django模板文档和其他文档，但它们没有解释如何做到这一点

我的想法是为用户类型的模型问题添加一个字段。因此，例如，Type=1问题可能对每个人都可见，而Type=2问题对他们添加到的组指定的用户子集可见

这是正确的方法吗？有没有类似的项目，我可以看看，但我没有找到。任何帮助都将不胜感激。提前谢谢

编辑：查看代码

# -*- coding: utf-8 -*-

from __future__ import (
    absolute_import, division, print_function, unicode_literals
)

from django.conf import settings
from django.shortcuts import get_object_or_404, redirect, render
from django.views.generic import View
from future import standard_library
from survey.forms import ResponseForm
from survey.models import Category, Survey

standard_library.install_aliases()



class SurveyDetail(View):

    def get(self, request, *args, **kwargs):
        survey = get_object_or_404(Survey, is_published=True, id=kwargs['id'])
        if survey.template is not None and len(survey.template) > 4:
            template_name = survey.template
        else:
            if survey.display_by_question:
                template_name = 'survey/survey.html'
            else:
                template_name = 'survey/one_page_survey.html'
        if survey.need_logged_user and not request.user.is_authenticated():
            return redirect('%s?next=%s' % (settings.LOGIN_URL, request.path))
        categories = Category.objects.filter(survey=survey).order_by('order')
        form = ResponseForm(survey=survey, user=request.user,
                            step=kwargs.get('step', 0))
        context = {
            'response_form': form,
            'survey': survey,
            'categories': categories,
        }

        return render(request, template_name, context)

    def post(self, request, *args, **kwargs):
        survey = get_object_or_404(Survey, is_published=True, id=kwargs['id'])
        if survey.need_logged_user and not request.user.is_authenticated():
            return redirect('%s?next=%s' % (settings.LOGIN_URL, request.path))
        categories = Category.objects.filter(survey=survey).order_by('order')
        form = ResponseForm(request.POST, survey=survey, user=request.user,
                            step=kwargs.get('step', 0))
        context = {'response_form': form, 'survey': survey,
                   'categories': categories}
        if form.is_valid():
            session_key = 'survey_%s' % (kwargs['id'],)
            if session_key not in request.session:
                request.session[session_key] = {}
            for key, value in form.cleaned_data.items():
                request.session[session_key][key] = value
                request.session.modified = True

            next_url = form.next_step_url()
            response = None
            if survey.display_by_question:
                if not form.has_next_step():
                    save_form = ResponseForm(request.session[session_key],
                                             survey=survey, user=request.user)
                    response = save_form.save()
            else:
                response = form.save()

            if next_url is not None:
                return redirect(next_url)
            else:
                del request.session[session_key]
                if response is None:
                    return redirect('/')
                else:
                    next_ = request.session.get('next', None)
                    if next_ is not None:
                        if 'next' in request.session:
                            del request.session['next']
                        return redirect(next_)
                    else:
                        return redirect('survey-confirmation',
                                        uuid=response.interview_uuid)
        if survey.template is not None and len(survey.template) > 4:
            template_name = survey.template
        else:
            if survey.display_by_question:
                template_name = 'survey/survey.html'
            else:
                template_name = 'survey/one_page_survey.html'
        return render(request, template_name, context)

---

您不需要在视图中编写一个只回答用户可以访问的问题的查询。以及对问题细节的许可，可以过滤出没有访问权限的用户

你能发布你的视图代码以便我们能提供更多帮助吗？抱歉-直到现在才看到这一点。我将用简短的代码更新我的问题。你能详细说明一下吗？如果我有一个视图，其中有一个查询响应用户权限和针对用户的权限，那么我还需要在问题中添加一个字段，例如，将问题与权限相关联的内容，对吗？是的，问题的某些字段需要区分哪些用户或用户组有权访问它。