使用django guardian for djangorestframework时权限不起作用

我试图使用django guardian将对象级权限添加到django REST项目中，但我得到了

HTTP 403禁止 允许：获取、发布、头、选项 内容类型：application/json 更改：接受

{ “详细信息”：“您没有执行此操作的权限。” }

用户joe已登录

settings.py：

INSTALLED_APPS = [
    'django.contrib.admin',
    'django.contrib.auth',
    'django.contrib.contenttypes',
    'django.contrib.sessions',
    'django.contrib.messages',
    'django.contrib.staticfiles',
    'django.contrib.sites',

    'guardian',
    'rest_framework',
    'rest_framework.authtoken',
    'rest_auth',

    'task.apps.TaskConfig',
]

models.py：

class Task(models.Model):
    summary = models.CharField(max_length=32)
    content = models.TextField()
    reported_by = models.ForeignKey(User, on_delete=models.CASCADE)
    created_at = models.DateTimeField(auto_now_add=True)

    class Meta:
        permissions = (
            ('view_task', 'View task'),
        )

serializers.py：

class TaskSerializer(serializers.ModelSerializer):
    class Meta:
        model = Task
        fields = '__all__'

permissions.py：

class CustomObjectPermissions(permissions.DjangoObjectPermissions):
    perms_map = {
        'GET': ['%(app_label)s.view_%(model_name)s'],
        'OPTIONS': ['%(app_label)s.view_%(model_name)s'],
        'HEAD': ['%(app_label)s.view_%(model_name)s'],
        'POST': ['%(app_label)s.add_%(model_name)s'],
        'PUT': ['%(app_label)s.change_%(model_name)s'],
        'PATCH': ['%(app_label)s.change_%(model_name)s'],
        'DELETE': ['%(app_label)s.delete_%(model_name)s'],
    }

filters.py：

class DjangoObjectPermissionsFilter(BaseFilterBackend):
    perm_format = '%(app_label)s.view_%(model_name)s'
    shortcut_kwargs = {
        'accept_global_perms': False,
    }

    def __init__(self):
        assert 'guardian' in settings.INSTALLED_APPS, (
            'Using DjangoObjectPermissionsFilter, '
            'but django-guardian is not installed.')

    def filter_queryset(self, request, queryset, view):
        from guardian.shortcuts import get_objects_for_user

        user = request.user
        permission = self.perm_format % {
            'app_label': queryset.model._meta.app_label,
            'model_name': queryset.model._meta.model_name,
        }

        return get_objects_for_user(
            user, permission, queryset,
            **self.shortcut_kwargs)

views.py：

class TaskViewSet(viewsets.ModelViewSet):
    queryset = Task.objects.all()
    serializer_class = TaskSerializer
    permission_classes = (CustomObjectPermissions,)
    filter_backends = (DjangoObjectPermissionsFilter,)

URL.py：

router = DefaultRouter()

router.register('tasks', TaskViewSet, base_name='tasks')

urlpatterns = router.urls

但它在贝壳里很好用

> python manage.py shell -i ipython
In [1]: from django.contrib.auth.models import User

In [2]: joe = User.objects.all().filter(username="joe")[0]

In [3]: import task.models as task_models

In [4]: task = task_models.Task.objects.all()[0]

In [5]: joe.has_perm('view_task', task)
Out[5]: True

首先是API，然后是它们是否适用。由于自定义权限类要求用户具有读取权限，因此需要确保已为Joe分配了模型级读取权限。如果您选中

joe.has\u perm（'tasks.view\u task'）

，我敢打赌它会返回

False

。要解决此问题，您需要直接为其用户分配权限，或者将其添加到已分配适当权限的组中

另外，请注意，Django 2.1最近添加了权限，不必再将其添加到模型中

首先是API，然后是API是否适用。由于自定义权限类要求用户具有读取权限，因此需要确保已为Joe分配了模型级读取权限。如果您选中

joe.has\u perm（'tasks.view\u task'）

，我敢打赌它会返回

False

。要解决此问题，您需要直接为其用户分配权限，或者将其添加到已分配适当权限的组中

另外，请注意，Django 2.1最近添加了权限，不必再将其添加到模型中