Elixir Phoenix Presence通过交替元模式跨多个通道跟踪用户
我正在构建一个whatsapp克隆,但我很难找到一些关于存在的东西 我有两个频道:Elixir Phoenix Presence通过交替元模式跨多个通道跟踪用户,elixir,phoenix-framework,user-presence,Elixir,Phoenix Framework,User Presence,我正在构建一个whatsapp克隆,但我很难找到一些关于存在的东西 我有两个频道: channel "chats:*", Typi.ChatChannel channel "users:*", Typi.UserChannel 用户始终连接到用户:…频道,如果他在应用程序中,在加入时,我开始跟踪他的状态: def join("users:" <> user_id, _payload, socket) do send self(), :after_join
channel "chats:*", Typi.ChatChannel
channel "users:*", Typi.UserChannel
用户始终连接到用户:…
频道,如果他在应用程序中,在加入时,我开始跟踪他的状态:
def join("users:" <> user_id, _payload, socket) do
send self(), :after_join
{:ok, socket}
end
def handle_info(:after_join, socket) do
Presence.track(socket, socket.assigns.current_user.id, %{})
{:noreply, socket}
end
当用户离开聊天室时,我想删除元信息,但保持状态。我该怎么做
谢谢实际上它是开箱即用的,下面的测试显示了这一点:
test "presence test", %{socket: socket, users: [john], chat: chat} do
{:ok, _, user_socket} = subscribe_and_join(socket, "users:#{john.id}", %{})
IO.inspect Presence.list(user_socket)
{:ok, _, chat_socket} = subscribe_and_join(socket, "chats:#{chat.id}", %{})
IO.inspect Presence.list(chat_socket)
IO.inspect Presence.list(user_socket)
end
测试的输出为:
%{"7939" => %{metas: [%{phx_ref: "UZDsMseg3as="}]}}
%{"7939" => %{metas: [%{chat_id: 1392, phx_ref: "sRhw30CJY1U="}]}}
%{"7939" => %{metas: [%{phx_ref: "UZDsMseg3as="}]}}
另外Presence.list(chat_socket)==Presence.list(“chats:{chat.id}”)
%{"7939" => %{metas: [%{phx_ref: "UZDsMseg3as="}]}}
%{"7939" => %{metas: [%{chat_id: 1392, phx_ref: "sRhw30CJY1U="}]}}
%{"7939" => %{metas: [%{phx_ref: "UZDsMseg3as="}]}}