Ember.js 使用createRecord在余烬数据中设置id

如果我尝试用以下内容创建一个记录

var myObject = App.ModelName.createRecord( data );
myObject.get("transaction").commit();

myObject的id从未设置

---

表示id生成应由EmberData处理（第一个响应）。那么应该发生什么呢？新id在哪里确定。是否应该回调API以获取有效id？

id是记录的主键，该记录是由数据库而不是由Ember创建的。这是JSON结构提交到REST帖子，注意没有ID

{"post":{"title":"c","author":"c","body":"c"}}

在REST Post函数中，必须获取最后一个insert ID，并使用以下JSON结构将其与模型数据的其余部分一起返回给Ember。请注意ID，这是最后一个插入ID。必须使用DB api手动获取最后一个插入ID

{"post":{"id":"20","title":"c","author":"c","body":"c"}}

这是我的REST帖子的示例代码。我使用PHP REST Slim框架对此进行了编码：

$app->post('/posts', 'addPost'); //insert new post

function addPost() {
    $request = \Slim\Slim::getInstance()->request();
    $data = json_decode($request->getBody());

    //logging json data received from Ember!
    $file = 'json1.txt';
    file_put_contents($file, json_encode($data));
    //exit;

    foreach($data as $key => $value) {
        $postData = $value;
    }

    $post = new Post();
    foreach($postData as $key => $value) {

        if ($key == "title")
            $post->title = $value;

        if ($key == "author")
            $post->author = $value;

        if ($key == "body")
            $post->body = $value;   
    }

    //logging
    $file = 'json2.txt';
    file_put_contents($file, json_encode($post));

    $sql = "INSERT INTO posts (title, author, body) VALUES (:title, :author, :body)";

    try
    {
        $db = getConnection();
        $stmt = $db->prepare($sql);
        $stmt->bindParam("title", $post->title);
        $stmt->bindParam("author", $post->author);
        $stmt->bindParam("body", $post->body);
        $stmt->execute();

        $insertID =  $db->lastInsertId(); //get the last insert ID
        $post->id = $insertID;

        //prepare the Ember Json structure
        $emberJson = array("post" => $post);

        //logging
        $file = 'json3.txt';
        file_put_contents($file, json_encode($emberJson));

        //return the new model back to Ember for model update
        echo json_encode($emberJson);
    }
    catch(PDOException $e)
    {
        //$errorMessage = $e->getMessage();
        //$data = Array(
        //  "insertStatus" => "failed",
        //  "errorMessage" => $errorMessage
        //);
    }
}

---

使用一些REST适配器，例如Firebase，您可以将id定义为要创建的记录的变量

App.User = DS.Model.extend({
  firstName: DS.attr('string')
});

var sampleUser = model.store.createRecord('user', {
  id: '4231341234891234',
  firstName: 'andreas'
});

sampleUser.save();

数据库中的JSON（Firebase）

"users": {
  "4231341234891234": {
    "firstName": "andreas"
  }
}